5-5-5--3-3--5-5--0--0-0---5-5-5--3-3--5-5--0
Bring all the unknown values to one side and the known values to the other 7s - 12 = 3s - 4 Subtract 3s from both sides 7s - 3s - 12 = 4 4s - 12 = 4 Add 12 to both sides 4s = 4 + 12 4s = 16 Divide both sides by 4 s = 4
5x7=35, then 3-1=2, so 35+2=37
You should split in blackjack when you have a pair of 2s, 3s, 6s, 7s, or 9s, according to the chart.
1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p
L + S = 72 so L = 72 - S; 4L - 3S = 78 ie 4(72 - S) - 3S = 78 ie 288 - 4S - 3S = 78 ie 7S = 210 so S = 30 and L = 42. And there you have it!
The order of electron orbitals following the Aufbau principle is: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, and 7p. Electrons fill the orbitals in increasing energy levels.
Endpoints: (s, 2s) and (3s, 8s) Midpoint: (2s, 5s) Slope: 3 Perpendicular slope: -1/3 Perpendicular bisector equation: 3y = -x+17s or as x+3y-17s = 0
It may be the Aufbau Principle if you are looking for specifics. or just an electron configuration with 1s, 2s, 2p, 3s, 3p, 3d, etc.
The answer is 7s + 49.
Puto
The equivalent is 7s+2s = 9s
Yes. The rumor right now is that there will be packs consisted of two pairs of Air Jordan 5s, two pairs of Air Jordan 7s, and a package that consist of the Jordan II and Jordan III. There is no word release dates or colorways. In addition to these three, there are some unconfirmed packs that may include a Hall of Fame Package and a couple of 3s packages (two pairs of Jordan 3s in one package). Yes. The rumor right now is that there will be packs consisted of two pairs of Air Jordan 5s, two pairs of Air Jordan 7s, and a package that consist of the Jordan II and Jordan III. There is no word release dates or colorways. In addition to these three, there are some unconfirmed packs that may include a Hall of Fame Package and a couple of 3s packages (two pairs of Jordan 3s in one package).