The energy is 103,6 kcal.
273 Kelvin is equal to a temperature of -0.15 degrees Celsius.K to C Formula: C = K - 273.15
273 Kelvin is equal to a temperature of -0.15 degrees Celsius.K to C Formula: C = K - 273.15
-273 degrees celsius is considered absolute zero, meaning that -273 degrees celsius (or 0 kelvin) is the lowest possible temperature.
The temperature should be varied from the initial temperature of the system and it reaches 273 K.
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A PWR has an inlet water temperature of 275 degC and outlet 325 degC
It would be approx 9042 litres.
Gases expand in proportion to the change in absolute temperature (deg kelvin). Thus if you took a volume of a gas at say 0 deg C (273 kelvin) and heated it to 273 deg C, that is doubling the degrees kelvin, keeping the pressure constant, the volume would double. Water on the other hand has a coefficient of expansion of 207 x 10-6 per deg Kelvin, so doubling its absolute temperature from 0 degC to 273 degC would only increase its volume by 5.65 x 10-2 = 0.0565, or 5.65 percent
Water is transformed in vapors.
(4.184 J/g*degC)(400g)(40.0*degC-80.0*degC)+(200g)
248.15 K
0
40
Add 273 to Celsius to get Kelvin. 273 + 37 = 310 K
The energy is 103,6 kcal.
In tokamak reactors, approx 300 million degC