All other factors being equal, the height of the column in a barometer is inversely related to the density of the material in that column. So we can write H = h (Rho/rho); where h = 745 mm Hg, H = ? mm in water, Rho = 13550 kg/m^3 Hg density and rho = 997 kg/m^3 water density.
So we have H = 745*(13550/997) = 10125.12538 mm ~ 10.1 m when all other factors are equal. ANS.
I assume you mean 740 mm Hg.
760 mm Hg = 760 Torr = 1 atmosphere.
Simply divide 740 by 760 and you will get the pressure in atmospheres.
740 mm Hg / 760 mm Hg = 0.97 atmospheres
The pressure of 754 mmHg at 0 degrees celsius is 100525.0657900325 pascals.
2% lower than normal (standard) pressure of 760 mm Hg
755 mmHG @0°C = 100,658Pa
1 Torr is the same as 1 mm Hg.
It is 98.7 kPa.
745 torr
.989
760 mm hg = 0 psi gauge pressure
1444 Torr=1444 MM Hg
-195mmHg
3.2 atmospheres = 2,432 mmHg
190 mm Hg
760 mm hg = 0 psi gauge pressure
1444 Torr=1444 MM Hg
152 mm Hg is equal to 0,2 atmosphere.
751,5 mm Hg is equal to 0,988 815 8 atmospheres.
-195mmHg
39.0
.2!
3.2 atmospheres = 2,432 mmHg
"mm Hg" stands for millimetres of mercury. Atmospheric pressure was measured in terms of the height of a column of mercury that it could support and by extension, mm Hg became a unit for measuring pressure.
The phrase "760 mm Hg" is physicists' shorthand for "an atmospheric pressure equal to that needed to support a column of mercury [chemical symbol Hg] of length 760 mm". This is approximately average atmospheric pressure at sea level. As the pressure decreases from "760 mm Hg" to "350 mm Hg", the volume of the gas will increase (assuming a constant temperature). The new volume can be determined using Boyle's Law: New Volume = 30 x 760 / 350 = 65.143 Litres
375mmhg
190 mm Hg