First, calculate the moles of each reactant: for Al2O3, it's 60.0g/(101.96 g/mol) and for C, it's 30.0g/(12.01 g/mol). Then find the limiting reactant by comparing the moles of each reactant and using the stoichiometry of the reaction. Aluminum would be the limiting reactant in this case. Finally, use the stoichiometry of the reaction to calculate the theoretical yield of aluminum, which is 2 moles of Al for every 1 mole of Al2O3.
The word equation for the reaction of iodine with aluminum to make aluminum iodide is: aluminum + iodine → aluminum iodide.
The chemical formula for aluminum fluoride is AlF3.
The chemical symbol for aluminum chloride is AlCl3.
Al2O3 is the chemical formula of aluminium oxide.
To determine the theoretical yield of aluminum oxide, we first need to write and balance the chemical equation: 4 Al + 3 O2 -> 2 Al2O3. From the equation, we can see that 4 moles of Al reacts with 3 moles of O2 to produce 2 moles of Al2O3. Calculate the moles of Al and O2 provided, convert each to moles of Al2O3, and find the limiting reactant to determine the theoretical yield.
The balanced chemical equation for the reaction is 4Al + 3O2 -> 2Al2O3. Since the molar ratio between aluminum and oxygen is 4:3, aluminum is the limiting reagent. Therefore, the theoretical yield of aluminum oxide is based on the 3.00 mol of aluminum. Using stoichiometry, the theoretical yield of aluminum oxide would be 3.00 mol of Al * (2 mol Al2O3 / 4 mol Al) = 1.50 mol of Al2O3.
The word equation for the reaction of iodine with aluminum to make aluminum iodide is: aluminum + iodine → aluminum iodide.
Aluminum (or aluminium) has Al as its chemical symbol.
The chemical name for aluminum bromide is aluminum tribromide, with the chemical formula AlBr3.
The chemical symbol for aluminum sulfide is Al2S3.
The balanced chemical equation for the reaction is 4Al + 3O2 → 2Al2O3. Since the stoichiometry ratio is 4:3, the limiting reactant is aluminum since it provides less moles of product. Therefore, 2.00 mol of aluminum will produce 2.00 mol of aluminum oxide.
The chemical symbol for aluminum is Al.
The chemical formula for aluminum chloride is AlCl3.
The chemical name for aluminum is aluminum (Al) and for chlorine is chlorine (Cl). When these two elements combine, they form aluminum chloride, which has the chemical formula AlCl3.
The balanced chemical equation for the formation of aluminum oxide is: 4Al + 3O2 -> 2Al2O3. This means that 4 moles of aluminum react with 3 moles of oxygen to produce 2 moles of aluminum oxide. Using the given moles of aluminum and oxygen, we can determine the limiting reactant and the theoretical yield of aluminum oxide. In this case, the oxygen is the limiting reactant, which means it will run out first. Therefore, all of the 2.70 mol of oxygen will react with aluminum to produce aluminum oxide. Since the ratio of aluminum to aluminum oxide is 4:2, the 2.70 mol of oxygen will react with (2/3)*2.70 mol of aluminum to produce aluminum oxide, which is approximately 1.80 mol.
The chemical formula for aluminum hydroxide is Al(OH)3.
The chemical formula for aluminum chloride is AlCl3.