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3mo ago

First, calculate the moles of each reactant: for Al2O3, it's 60.0g/(101.96 g/mol) and for C, it's 30.0g/(12.01 g/mol). Then find the limiting reactant by comparing the moles of each reactant and using the stoichiometry of the reaction. Aluminum would be the limiting reactant in this case. Finally, use the stoichiometry of the reaction to calculate the theoretical yield of aluminum, which is 2 moles of Al for every 1 mole of Al2O3.

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Q: What is the theoretical yield of aluminum that can be produced by the reaction of 60.0 g of aluminum oxide with 30.0 g of carbon according to the following chemical reaction Al2O3 3C 2Al 3CO?
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