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ml = -1
The Specific orbital the electron is in
Zero. First n=3; second l = 0; third m = 0.
n = 2, l = 0, ml = 0, ms = -1/2 Only the radial function R(r) of the Schrodinger wave function (psi) is needed to calculate the Energy. The radial function only deals with the principle quantum number (n). Therefore, only n is required to find the Energy. As to find the Energy states, one must specify if we are dealing with a one-electron atom situation or multiple-electron system. For one-electron atoms, the Energy states is determined by the principle quantum number (n). For multi-electron systems, the Energy states depend on both the principle quantum number (n) and orbital quantum number (l). This explanation is valid unless we are using very high resolution spectroscopic techniques, deviations will appear.
n is the first quantum number. It is the principle quantum number. It refers to what energy level it is and will be one greater than the number of nodes in the orbital. l is the second quantum number. It is the angular momentum quantum number and refers to the shape of the orbital. ml is the third quantum number. It is the magnetic quantum number and it refers to the orientation of the orbital. ms is the fourth quantum number. It is the spin quantum number and refers to the magnetic character of the orbital.
mi=0
Mi=0
ml = -1
mi=0
ml = -1
ml = 0
the answer is m1+=0
m(I)=0 (apex)
The Specific orbital the electron is in
The specific orbital the electron is in
The Specific orbital the electron is in
The shape of the electron cloud is determined by the secondary quantum number. The first is n, or the energy level, the second is the sublevel, the third is the specific cloud, and the fourth is the spin.