Francium has 87 electrons; one is the valence electron.
7s1 because the definition of valence electrons are the outermost s and p electrons therefore in this case there is only an outermost s electron and therefore the answer is 7s1. NOTE:IT DOES NOT INCLUDE THE D AND THE F ELECTRONS!!!!Other valence configuration examples include;Nitrogen : 2s2 2p3Chlorine : 3s2 2p5Zinc: 4s2Bromine: 4s2 4p5
Francium has 87 electrons but the atom is neutral.
To find the total number of valence electrons in Li2O, we add the valence electrons of lithium (1 valence electron each) to the valence electrons of oxygen (6 valence electrons). So, Li2O has 2 (from Li) + 6 (from O) = 8 valence electrons.
Calcium has a total of two valence electrons.
To find the number of non-valence electrons in an atom, you first need to determine the total number of electrons in the atom by looking at its atomic number on the periodic table. Next, subtract the number of valence electrons, which are the electrons in the outermost energy level of the atom, from the total number of electrons. The remaining electrons, which are not in the outermost energy level, are the non-valence electrons.
The beryllium atom has 4 electrons and the valence is 2.
Boron has 3 valence electrons out of five total electrons.
I (if you count the rows) is at the 7th row, so it has 7 valence electrons. The is the same for Br, so there is a total of 14 electrons. :)
Helium has 2 electrons (total of 2 electrons and 2 valence electrons)
NO2 Nitrogen has 5 valence electrons Oxygen has (6*2) =12 valence electrons therefore, the total number of valence electron =12 +5 = 17valence electrons.
Each H has 1. Each O has 6 and the S has 6. That's a total of 32 valence electrons.
Potassium (K) has 1 valence electron and Bromine (Br) has 7 valence electrons. Therefore, the total number of valence electrons in KBr is 1 (from K) + 7 (from Br) = 8 valence electrons.