It is a flag character that precedes the variable type place holder.
%d %i Decimal signed integer.
%o Octal integer.
%x %X Hex integer.
%u Unsigned integer.
%c Character.
%s String. See below.
%f double
%e %E double.
%g %G double.
%p pointer.
%% %. No argument expected.
It is a function.
I believe, you can use C-function - printf().
putc('%'); write(1, "%", 1); printf("%%"); printf("%c", '%'); will all each put a % character (percent sign) on stdout.
if (a > b && a > c) printf("%d\n", a); else if (b > c) printf("%d\n", b); else printf("%d\n", c);
int f(int num) { int i; for (i = 0; i < 10; i++) { if (num > i) continue; printf("aaa"); } } printf will only be reached when i <= num.
try to usecondition ? value if true : value if falseor: if (printf ("Hello")) {}
putchar ('%'); puts ("%"); printf ("%%"); etc...
Answerwell if it is about the include statement only then your answer goes simple. extern "C"{int printf(const char *format,..);}int main(){printf("Hello world");}coz all the include statement does is copy the requested file at the asked location.
The C language uses the ending curly brace to mark the end of an "if" statement, in the same place that other languages use "endif":int main(void){int bunnies = 2;if( bunnies ){printf("Hop, Hop\n");};printf( "Goodbye.\n" );}
%f is used as a format mask to represent a floating point number.Any of the "formatted" io functions can use this: printf, fprintf, scanf, etc.Example:float n = 1.5;printf("%f", n); // prints the value of n
You can use fputs() instead of printf().
#include<stdio.h> #include<conio.h> int main(void) { int a,b,c; printf("write three numbers:\n"); scanf("%d %d %d", &a,&b,&c); printf("You entered %d , %d and %d",a,b,c); getch(); }