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The accepted value for the heat of solution of NaOH is -44.2 kJ/mol
C4H10(g) is about -126 kJ/mol C4H10(l) is about -147 kJ/mol
The value is not so low: 499 kJ/mol.
R = 0.082 ATM L/mol K
82 degrees Celsius
G=18 kJ/mol
G = 18 kJ/mol
18 kJ/Mol
-18 kj/mol
H = 28 kJ/mol, S = 0.109 kJ/(molK)
It is not spontaneous.
It is spontaneous at 2000 K.
DeltaG = DeltaH - TDeltaS dG = -54.32 kJ/mol - (54'32+273)K(-354.2J/molK) NB Thevtemperature is quoted in Kelvin(K) and the Entropy must be converted to kJ by dividing by '1000'/ Hence dG = - 54.32kJ/mol - (327.32K)(-0.3542 kJ/molK) NB The 'K' cancels out. Then maker the multiplication dG = -54/32 kJ/mol - - 115.94 kJ/mol Note the double minus; it becomes plus(+). Hence dG = -54.32kj/mol + 115.94 kJ/mol dG = (+)61.61 kJ/mol Since dG is positive, the reaction is NOT thermodynamically feasible.
It is spontaneous.
Use PV =nRT ( pressure at STP is 1 atmosphere and temp. is 298.15 Kelvin ) (1 atm)(volume) = (1.50 mole)(0.08206 Latm/molK)(298.15 K) = 36.7 Liters
The standard enthalpy of formation for sodium chloride is -411,12 kJ/mol.
Approximately -82kJ/mol