I'm not sure if it's ever measured, but it could be approximated by calculating the surface gravity of a spherical asteroid of equal mass and dimensions.
Assuming the mass of the International Space Station is 450 000 kg (M) and its mean radius is about 30 meters (r) , the surface gravity would be g = MG/r2 = about 0,00000003337 m/s2 (about 30 nanometers/square second).
For comparison, Earth's surface gravity is about 9.81 m/s2, so the gravity you would experience standing on the surface of the International Space Station is about 0.3 millionth of a percent compared to earth. It's certainly too small a gravity to hold you attached to the station if you were standing on it.
If you're inside the space station, in the center of the station, there is zero gravity because you are in the center of gravity because the mass of the station is situated around you.
Panu, M.Sc.
It is a laboratory in space. Earth has many of them orbiting it. The International Space Station (ISS) has several labs dedicated to research of space, the sun, plants and animals' reaction to space and new materials invented in zero g.
The ISS is used for various research projects and experiments that can only be performed in micro-gravity. (free-fall, or zero G)
The values of g would decrease once getting closer to the axis. At the axis it would be 0g
If the size of the space station is large enough, then the astronaut will detect the change in Earth's gravity (g).
1.5
It is a laboratory in space. Earth has many of them orbiting it. The International Space Station (ISS) has several labs dedicated to research of space, the sun, plants and animals' reaction to space and new materials invented in zero g.
The ISS is used for various research projects and experiments that can only be performed in micro-gravity. (free-fall, or zero G)
The values of g would decrease once getting closer to the axis. At the axis it would be 0g
The most meaningful answer is zero G. You, the space-station and everything in it are in free-fall towards Earth. All are 'weightless' (but not massless).
Folk on the International Space Station live in a zero G environment, and suffer from muscle and bone wastage as a result, in spite of keeping up an exercise regime.
G. S. Nurre has written: 'A TREETOPS simulation of the STABLE microgravity vibration isolation system' -- subject(s): Control theory, Vibration isolators, Microgravity, Research facilities, Nonlinearity, International Space Station, Flight tests
G. Paul Richter has written: 'Proven, long-life hydrogen/oxygen thrust chambers for space station propulsion' -- subject(s): Space stations, Propulsion systems, Space vehicles
Many types of plants have been germinated in space aboard the Space Shuttle and the International Space Station. I was unable to find any information on anyone attempting to grow pumpkins to fruition, but it is theoretically possible, as long as you can account for providing water and nutrients in a zero-g environment, and can provide an adequate light source.
If the size of the space station is large enough, then the astronaut will detect the change in Earth's gravity (g).
The colony must provide everything that an orbiting Space Station must provide, except that the special toilets needed for Zero-G on the Space Station should not be necessary and more normal toilets could be used.
The gravitational pull decreases in inverse proportion to the square of distance from the centre of the earth, thus it would speedily decrease as we go away from earth but never become zero anywhere, it remains, in however small quantities. Say, 160 km from the surface of the earth, the gravitational pull would be 0.95 times that at the surface of the earth (which is 9.81 m/s2). At 400 km from the earth (where the International Space Station seems to be floating), it would be 0.88 times that which is at the surface of the earth. Near moon, it would be .000272 times of what we feel here. Now, the weightlessness they feel on the International Space Station is due to the fact that the Space Station is circling around earth once in 91 minutes. The centrifugal force compensates for the remaining 0.88 g gravity there.
9.8 is the value for g, which stands for Gravity.