Want this question answered?
Kb=[HCn][OH-] [CN-]
Kb=[HCN][OH-]/[CN-]
Kb = 55 It is a very strong base therefore it completely dissociates.
3.2 x 10-5
The strength of an acid is expressed by its Ka value (acid 'equilibrium' constant) or its derivative pKa value ( pKa=-log10[Ka] )The relation with the strength of the conjugate base, (Kb , pKb values) is as follows:Ka * Kb = 1.0*10-14 at 25oCpKa + pKb = 14.00 at 25oC
NaCN doesn't really have a pKa. In water it becomes Na^+ and CN^-. The CN^- is a base so it will have a Kb and pKb. If you want the pKa of the conjugate acid (HCN), you can find that from 1x10^-14/Kb.
Kb=[HCn][OH-] [CN-]
Kb=[HCN][OH-]/[CN-]
Kb = 3.8 10-10
Kb = 55 It is a very strong base therefore it completely dissociates.
2.2 x 10-8
3.2 x 10-5
The strength of an acid is expressed by its Ka value (acid 'equilibrium' constant) or its derivative pKa value ( pKa=-log10[Ka] )The relation with the strength of the conjugate base, (Kb , pKb values) is as follows:Ka * Kb = 1.0*10-14 at 25oCpKa + pKb = 14.00 at 25oC
3.2 x 10-5
4.0 x 10-11
4.0 x 10-11
The constants Ka and Kb relate to the relative strengths of series of acids or bases by being proportional. The higher the Ka or Kb value, the stronger the acid or base.