Kb=[HCN][OH-]/[CN-]
The Kb for CN- (aq) is the equilibrium constant for the reaction of CN- with water to form HCN (aq) and OH- (aq). It represents the strength of the base CN- in solution. It can be calculated by taking the concentration of the products (HCN and OH-) and dividing by the concentration of CN- at equilibrium.
ka=[H+][CN-]/[HCN]
NH4OH + HC2H3O2 ---> NH4C2H3O2 + H2ONH4+ + OH- + H+ + C2H3O2- ---> NH4+ + C2H3O2- + H2OOH- (aq) + H+ (aq)---> H2O (l)
The net ionic equation for the reaction is: CN^- + H^+ -> HCn
NaCN + H2O ---> CN-+ H3O++ Na+ In that equation Na+ is just a spectator ion,, further reaction with water results in: CN- + H2O ---> HCN + OH- thus causing the resulting equation to be basic
The Kb for CN- (aq) is the equilibrium constant for the reaction of CN- with water to form HCN (aq) and OH- (aq). It represents the strength of the base CN- in solution. It can be calculated by taking the concentration of the products (HCN and OH-) and dividing by the concentration of CN- at equilibrium.
ka=[H+][CN-]/[HCN]
HCN(aq) ==> H^+(aq) + CN^-(aq)Ka = [H+][CN-]/[HCN] and the value can be looked up in a book or on line.
NH4OH + HC2H3O2 ---> NH4C2H3O2 + H2ONH4+ + OH- + H+ + C2H3O2- ---> NH4+ + C2H3O2- + H2OOH- (aq) + H+ (aq)---> H2O (l)
The acid in the reaction is hydrogen cyanide (HCN), which is formed when cyanide ion (CN-) reacts with water (H2O) to release hydroxide ion (OH-).
The eqnet ionic equation is HCN + OH- --> H2O + CN-
The net ionic equation for the reaction is: CN^- + H^+ -> HCn
NaCN + H2O ---> CN-+ H3O++ Na+ In that equation Na+ is just a spectator ion,, further reaction with water results in: CN- + H2O ---> HCN + OH- thus causing the resulting equation to be basic
NaCN doesn't really have a pKa. In water it becomes Na^+ and CN^-. The CN^- is a base so it will have a Kb and pKb. If you want the pKa of the conjugate acid (HCN), you can find that from 1x10^-14/Kb.
The Lewis dot structure of HCN (hydrogen cyanide) has the hydrogen atom bonded to the carbon atom with a single bond and the carbon atom bonded to the nitrogen atom with a triple bond. Each atom has a full valence shell, with hydrogen having 2 valence electrons, carbon having 8 valence electrons, and nitrogen having 8 valence electrons.
HCN - Hydrogen cyanide The conjugate acid of CN- is HCN. HCN stands for hydrogen cyanide. The conjugate acids are a combination of a strong acid and a low base.
The conjugate base of hydrocyanic acid (HCN) is cyanide ion (CN-). When HCN donates a proton, it forms CN-.