Write out the equation in words. The operators do not show in the question.
3 18 divided by 6 is 3.
The value of 'n' is 6
If you mean: 24 - x/6 = -5 then the value of x works out as 174
t(n) = 24/2n, n = 1, 2, 3, ...
3/4 = 6/8
6
If you mean: -4*(n-6) = 12 then the value of n = 3
m + n = 6 mn = 24 Hence m = 24/n Substitute 24/n + n = 6 Multiply through by 'n' 24 + n^2 = 6n n^2 - 6n + 24 = -0 This does NOT factor so apply the Quadratic Equation. n ={--6+/- sqrt[(-6)^2 - 4(1)(24)]} / 2(1) n = {6 +/- sqrt[36 - 96]} / 2 n = {6 +/- sqrt[-60]} / 2 We now move into imaginary numbers, designated by 'i' (= sqrt(-1) . Hence n = {6 +/- i sqrt(60)} / 2 n = {6 +/- i(7.74596...)} / 2 n = 3 +/- 3.87298... i Hence n = 3 + 3.87298...i & 3 - 3.87298 ... i
n+6
3 18 divided by 6 is 3.
The value of 'n' is 6
If you mean: -4*(n-6) = 12 then the value of n = 3
2n + 6 = 3 + n ; this is an equation of one variable {n}. It can be solved for a value of n:subtract n fro both sides: 2n + 6 - n = 3 + n - n ---> n + 6 = 3.subtract 6 from both sides: n + 6 - 6 = 3 - 6 ---> n = -3. You should then substitute n=-3 back into the original to check your work.2(-3) + 6 = -6 + 6 = 0 | 3 + (-3) = 0, so it checks out.
n = 6, 12, 18, 24
0 6 24 60 120 n^3-n (n is the position) One could see it in this way too: 0*1*2=0 1*2*3=6 2*3*4=24 3*4*5=60 4*5*6=120 So basically it is ((n*(n+1)*(n+2)) where n=0,1,2.......
t(n) = 6*n where n = 1, 2, 3, etc
If you mean: 24 - x/6 = -5 then the value of x works out as 174