Simply divide the voltage by the current. This means you apply Ohm's Law.
20V / 5ohms = 4A
Convert the current to amperes, then (using Ohm's Law), divide voltage by current.
QUESTION (continued from above) ....The battery has negligible resistance and its open-circuit voltage is 20V. Determine the resistance, if the current to the battery is to be limited to 25A.
-20v + 4v2 - 5y + vy = 4v2 - 20v + vy - 5y = 4v*(v - 5) + y*(v - 5) = (4v + y)*(v - 5)
2627mm = 2000d = 500c = 100xx= 20v= 5ii= 2mmdcxxvii:= 2000 + 500 + 100 + 20 + 5 + 2= 2627
yes if you add two 20V/1W zener in parallel you will arrive 20V/2W
AE86's!
Put the 1V and 5V to the x2.Put the 1V and 20V to the x3.Put the 5V and 20V to the x1.See related link for screenshots.
rated for 20 volts?
rated for 20 volts?
Put the 1V and 5V to the x2.Put the 1V and 20V to the x3.Put the 5V and 20V to the x1.See related link for screenshots.
The firing order of the 5 cylinder 2.0 litre 20V Coupé is: 1-2-4-5-3 (the turbo version is the same).