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What is the value of g at a distance of twice the earth's radius if the value of g on the earth's survace is about 9.8 meters per second squared?
Wiki User
∙ 12y ago
We know that,
g1=G.m/R2
so, g is inversely proportional to R2.
And, if Radius of the earth(R) is doubled, the distance between the object and the centre of the earth will become 2R.
Now, g=G.m/(2R)2
=> g2=G.m/4R 2
=> g2=1/4(G.m/R2)
Since, G.m/R2 =g1
=> g2=1/4 g1
Here, g1=9.8 m/s2
So, g2=9.8/4 m/s2
=2.45 m/s2
Wiki User
∙ 12y ago
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