We'll assume that the 5,000 joules represents all Kinetic Energy of the car's motion,
and there's no potential energy, energy stored in the battery, or gas-in-the -tank
energy included in that number.
Kinetic Energy = (1/2) (m) (V2)
V2 = 2 KE / m
V = sqrt( 2 KE / m ) = sqrt( 10,000 / 400 ) = sqrt(25) = 5 meters per second
Kinetic Energy = 1/2 * mass * velocity squared
KE = 1/2mV2
KE = 1/2(500 kg)(5 m/s)
= 6250 Joules
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At least 5,000 J.
Work = (force) x (distance) = 7 x 2.4 = 16.8 joules
400 Octillion Joules. (400,000,000,000,000,000,000,000,000,000) It's not really a fair question, however. The Death Star, as depicted in the Star Wars movies, is grossly overpowered for its purpose. It would take a tiny fraction of that energy to simply vaporize the surface and wipe out all life. Okay, I admit I did not actually calculate the energy required to vaporize a planet. I simply assumed that the energy output of a Sun like star would be sufficient if it were all turned on puny little Alderaan (or Earth). The Sun outputs 400 Octillion Joules / second.
Ek = 1/2*m*v^2, where Ek is kinetic energy, m is mass, and v is velocity. Therefore, 1/2*20*2^2 = 40 Joules.The formula Ek =1/2*m*v^2 can be used for any point mass, that is, a mass that is small enough that it can be considered to have all its mass in one point, or a solid object that is not rotating.
KE = 1/2mass velocity squared KE = 1/2mV^2 80 J = 1/2(10 kg)V^2 multiply through by 2 160 = 10V^2 divide by 10, both sides 16 = V^2 take square root each side and discard negative answer Velocity = 4 m/s
400 mL
1,000 J
KE = 1/2 M V2 = 1/2 (2) (20)2 = 400 kg-m2/sec2 = 400 joules
400 joules.
kinetic energy is 1/2mv^2, our velocity is 20 m/s , our mass is 2000 kg. Plugging it in you get 1/2 (2000) (400) = 1000 * 400 = 400000 joules
The kinetic energy E of a body with mass m and velocity v is defined as E = mv2/2 You can write this formula as v2 = 2E/m So to obtain the velocity of the object at the base of the swing, take the square root of 2E/m.
joules is energy, not a force
kinetic energy is 1/2mv^2, our velocity is 20 m/s , our mass is 2000 kg. Plugging it in you get 1/2 (2000) (400) = 1000 * 400 = 400000 joules
velocity Kinetic energy is equal to (1/2)mv2, where m is mass and v is velocity. Higher velocities contribute even more to higher kinetic energies than higher masses since velocity is squared in the equation. For comparison, a 6.35 kg bowling ball moving at 7.6 m/s will have a kinetic energy of 183.4 Joules. A 0.02 kg bullet moving at 200 m/s will have a kinetic energy of 400 Joules. (Increase that to 300 m/s, and the kinetic energy moves up to 900 Joules.)
400/500 = 80% efficient
Initial kinetic energy = 1/2 M Vi2 Final kinetic energy = 1/2 M Vf2 Difference = 1/2 M (Vf2 - Vi2) = 2,500(302 - 202) = 2,500(900 - 400) = 2,500 x 500 = 1,250,000 joules
400 over 5000 is 2 over 25.
1 Joule is 1 Watt-Second. 1 Watt Hour is 3600 Watt-Second or 3600 Joules. 400 Watt-Hours is 1440000 Joules.