500 metres per second.
29.4
29.4 m/s
5*9.8 = 49 metres per second.
In skydiving, the standard time to reach terminal velocity is about 12 seconds. Of course, "your mileage may vary....."
At gravity's rate of 9.8m/s , after ten seconds it would be 98 m/s theoretically, although also a variable is terminal velocity.
29.4
194fps
1g, 9.82 m s^-2, gives a 0-60 (mph) time of 2.73 seconds, from rest, assuming negligible air resistance. Not many cars can do that.
29.4 m/s
A freely falling Ball has the acceleration of 9.8 m/s/s so after 5 seconds its velocity will be: t=5s a=9.8m/s/s v=5s * 9.8m/s/s =49 m/s
On Earth gravity equals 9.8 m/s^2. If you multiply that by 8 seconds you get: 78.4m/s
the answer is 24-9 m/sec. yuor welcome
At the end of 3 seconds, a falling object is falling at 65.8 mph faster than when it was released, ignoring air resistance.
Ignoring air resistance and using g = 9.81 ms-2, velocity = 20.38 ms-1.
5*9.8 = 49 metres per second.
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In skydiving, the standard time to reach terminal velocity is about 12 seconds. Of course, "your mileage may vary....."