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What is the velocity of a stone dropped of a building 318 meters?
Wiki User
∙ 12y ago
Ignoring any effects due to air resistance, the speed of the stone is zero at the
instant it's dropped, and increases steadily to 78.98 meters per second when it
hits the ground. The velocity is directed downward throughout the experiment.
Wiki User
∙ 12y ago
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A stone that is initially t rest is dropped from the top of a building ot falls for 5.0 s before hotting the ground how tall is the building?
You have to let me ignore air-resistance for this one. Since I don't know anything about the shape or size of the stone, I can't calculate any effects of air. Initial velocity = 0 Final velocity = 5 x acceleration = 5 x G = 5 x (9.8 meters / sec2) = 49 meters per second Average velocity during the fall = 1/2 x ( 0 + 49 ) = 24.5 meters per second Distance of the fall = (24.5 meters per second) x (5 seconds) = 122.5 meters = 401.9 ft(approx., rounded)
Is the speed uniform or nonuniform of a stone dropped from a height?
The speed of a dropped stone will be non-uniform. The stone goes faster as it falls by an amount equal to 32 feet per second, per second. That means for each second of falling, the speed increases by another 32 feet per second until terminal velocity is reached.
What is the acceleration of the stone if it is dropped from the top of a tower?
The acceleration will be equal to the acceleration due to gravity. Unless otherwise stated, one can assume this to be 9.81 meters/seconds It has nothing to do with the mass of the stone.
When a body is projected simultaneously from the top of the building with different initial horizontal velocity which of the two will hit the ground first?
Ignoring air resistance, the horizontal component of velocity has no connection with, and no effect on, the vertical component. Two bodies that leave the top of the building simultaneously with the same vertical velocity hit the ground at the same time, regardless of their horizontal velocities or their masses. That's the same as saying that a bullet fired horizontally from a gun and a bullet or a stone dropped from the gun's muzzle at the same instant hit the ground at the same instant. Strange but true.
Do you agree with the statement an object with a zero velocity can have an acceleration greater than yero?
Of course. Toss a stone straight up. -- From the moment it leaves your hand until the moment it hits the ground, it has constant acceleration ... the acceleration of gravity, around 10 meters per second2. The number isn't important, only the fact that the acceleration of the stone is not zero until it hits the ground. -- Velocity-wise: The stone starts out with some upward velocity, which steadily decreases until it's at the top of its arc, then the velocity becomes downward and increases until the stone hits the ground. -- At the very top of the arc, there is a point where the velocity changes from upward to downward. In order for that to happen, there must be an instant when the velocity is zero. -- But the acceleration is constant and not zero, even at that instant when the velocity is zero.
A stone that is initially at rest is dropped from the top of a building it falls for 5.0s before hitting the ground how tall is the building?
The building is h=.5 gt^2 meters tall; that is = .5x9.8 x25 =122.5 meters.
A stone that is initially t rest is dropped from the top of a building ot falls for 5.0 s before hotting the ground how tall is the building?
You have to let me ignore air-resistance for this one. Since I don't know anything about the shape or size of the stone, I can't calculate any effects of air. Initial velocity = 0 Final velocity = 5 x acceleration = 5 x G = 5 x (9.8 meters / sec2) = 49 meters per second Average velocity during the fall = 1/2 x ( 0 + 49 ) = 24.5 meters per second Distance of the fall = (24.5 meters per second) x (5 seconds) = 122.5 meters = 401.9 ft(approx., rounded)
How long does a stone take to fall 100 meters?
it depends on the weight on the stone, the wind speed at the time, the strength of velocity, etc.
If a stone is dropped from the top of a 140 meter building what is its speed when it is 20 meters above the ground?
Assume that acceleration due to gravity, g = 9.8 ms-2. v2 = u2 + 2gs u, the initial velocity is 0 ms-1, s, the distance travelled is 140 - 20 = 120 m. So v2 = 2352 m2 so that v = 48.5 ms-1 approx.
When is meant by accleration due to gravity?
Dropping a stone from a tall building is an example of acceleration due to gravity. The stone's speed will increase as it falls until it reaches terminal velocity.
Is the speed uniform or nonuniform of a stone dropped from a height?
The speed of a dropped stone will be non-uniform. The stone goes faster as it falls by an amount equal to 32 feet per second, per second. That means for each second of falling, the speed increases by another 32 feet per second until terminal velocity is reached.
What is the acceleration of the stone if it is dropped from the top of a tower?
The acceleration will be equal to the acceleration due to gravity. Unless otherwise stated, one can assume this to be 9.81 meters/seconds It has nothing to do with the mass of the stone.
When a body is projected simultaneously from the top of the building with different initial horizontal velocity which of the two will hit the ground first?
Ignoring air resistance, the horizontal component of velocity has no connection with, and no effect on, the vertical component. Two bodies that leave the top of the building simultaneously with the same vertical velocity hit the ground at the same time, regardless of their horizontal velocities or their masses. That's the same as saying that a bullet fired horizontally from a gun and a bullet or a stone dropped from the gun's muzzle at the same instant hit the ground at the same instant. Strange but true.
Is Dropped like a stone a metaphor or simile?
"Dropped like a stone" is a simile because it uses "like" to compare the action of dropping to a stone.
How high is the cliff is a stone is dropped from the top of a cliff It hits the ground below after 3.10 s?
Let Vo = initial velocity = 0 (m/s) x = vertical displacement t = time and a = gravitational constant = 9.8 meters per second squared (m/s2) x= initial velocity * time + 1/2 acceleration * time squared = Vot + (1/2)at2 = (0*3.1) + (1/2)(9.8)(3.1)(3.1) = 47.089 meters (metric) = 154.5 feet (English conversion)
Do you agree with the statement an object with a zero velocity can have an acceleration greater than yero?
Of course. Toss a stone straight up. -- From the moment it leaves your hand until the moment it hits the ground, it has constant acceleration ... the acceleration of gravity, around 10 meters per second2. The number isn't important, only the fact that the acceleration of the stone is not zero until it hits the ground. -- Velocity-wise: The stone starts out with some upward velocity, which steadily decreases until it's at the top of its arc, then the velocity becomes downward and increases until the stone hits the ground. -- At the very top of the arc, there is a point where the velocity changes from upward to downward. In order for that to happen, there must be an instant when the velocity is zero. -- But the acceleration is constant and not zero, even at that instant when the velocity is zero.
When a stone is thrown upward at an angle what happens to the vertical component of its velocity as it rises and as it falls?
The vertical component of its velocity increases at the rate of 9.8 meters (32.2 feet) per second downward every second. Without involving numbers, simply the vertical component will first be upward at what ever velocity it is when split from the horizontal velocity, then (after reaching the peak of its height at which velocity is zero) it will be a downward vector that, yes, will increase with acceleration due to gravity (which is where the 9.8 meters per second squared came from)
