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A stone that is initially t rest is dropped from the top of a building ot falls for 5.0 s before hotting the ground how tall is the building?
You have to let me ignore air-resistance for this one. Since I don't know anything about the shape or size of the stone, I can't calculate any effects of air. Initial velocity = 0 Final velocity = 5 x acceleration = 5 x G = 5 x (9.8 meters / sec2) = 49 meters per second Average velocity during the fall = 1/2 x ( 0 + 49 ) = 24.5 meters per second Distance of the fall = (24.5 meters per second) x (5 seconds) = 122.5 meters = 401.9 ft(approx., rounded)
Is the speed uniform or nonuniform of a stone dropped from a height?
The speed of a dropped stone will be non-uniform. The stone goes faster as it falls by an amount equal to 32 feet per second, per second. That means for each second of falling, the speed increases by another 32 feet per second until terminal velocity is reached.
When a stone is thrown upward at an angle what happens to the vertical component of its velocity as it rises and as it falls?
The vertical component of its velocity increases at the rate of 9.8 meters (32.2 feet) per second downward every second. Without involving numbers, simply the vertical component will first be upward at what ever velocity it is when split from the horizontal velocity, then (after reaching the peak of its height at which velocity is zero) it will be a downward vector that, yes, will increase with acceleration due to gravity (which is where the 9.8 meters per second squared came from)
What is the acceleration of the stone if it is dropped from the top of a tower?
The acceleration of the stone when it is dropped from the top of a tower is equal to the acceleration due to gravity, which is approximately 9.8 m/s^2 downward. This acceleration remains constant as the stone falls towards the ground, neglecting air resistance.
What will happen to a stone dropped from the roof of a single story building to the surface of the earth?
The stone would fall straight down from the release point, it would fall with steadily increasing speed, and when it hit the ground, it would stop falling. The rate at which its speed increased during the fall would be 32.2 feet per second faster every second.
A stone that is initially at rest is dropped from the top of a building it falls for 5.0s before hitting the ground how tall is the building?
The building is h=.5 gt^2 meters tall; that is = .5x9.8 x25 =122.5 meters.
How long does a stone take to fall 100 meters?
it depends on the weight on the stone, the wind speed at the time, the strength of velocity, etc.
A stone that is initially t rest is dropped from the top of a building ot falls for 5.0 s before hotting the ground how tall is the building?
You have to let me ignore air-resistance for this one. Since I don't know anything about the shape or size of the stone, I can't calculate any effects of air. Initial velocity = 0 Final velocity = 5 x acceleration = 5 x G = 5 x (9.8 meters / sec2) = 49 meters per second Average velocity during the fall = 1/2 x ( 0 + 49 ) = 24.5 meters per second Distance of the fall = (24.5 meters per second) x (5 seconds) = 122.5 meters = 401.9 ft(approx., rounded)
If a stone is dropped from the top of a 140 meter building what is its speed when it is 20 meters above the ground?
Assume that acceleration due to gravity, g = 9.8 ms-2. v2 = u2 + 2gs u, the initial velocity is 0 ms-1, s, the distance travelled is 140 - 20 = 120 m. So v2 = 2352 m2 so that v = 48.5 ms-1 approx.
Is the speed uniform or nonuniform of a stone dropped from a height?
The speed of a dropped stone will be non-uniform. The stone goes faster as it falls by an amount equal to 32 feet per second, per second. That means for each second of falling, the speed increases by another 32 feet per second until terminal velocity is reached.
When is meant by accleration due to gravity?
Dropping a stone from a tall building is an example of acceleration due to gravity. The stone's speed will increase as it falls until it reaches terminal velocity.
When a stone is thrown upward at an angle what happens to the vertical component of its velocity as it rises and as it falls?
The vertical component of its velocity increases at the rate of 9.8 meters (32.2 feet) per second downward every second. Without involving numbers, simply the vertical component will first be upward at what ever velocity it is when split from the horizontal velocity, then (after reaching the peak of its height at which velocity is zero) it will be a downward vector that, yes, will increase with acceleration due to gravity (which is where the 9.8 meters per second squared came from)
Is Dropped like a stone a metaphor or simile?
"Dropped like a stone" is a simile because it uses "like" to compare the action of dropping to a stone.
How high is the cliff is a stone is dropped from the top of a cliff It hits the ground below after 3.10 s?
Let Vo = initial velocity = 0 (m/s) x = vertical displacement t = time and a = gravitational constant = 9.8 meters per second squared (m/s2) x= initial velocity * time + 1/2 acceleration * time squared = Vot + (1/2)at2 = (0*3.1) + (1/2)(9.8)(3.1)(3.1) = 47.089 meters (metric) = 154.5 feet (English conversion)
What is the acceleration of the stone if it is dropped from the top of a tower?
The acceleration of the stone when it is dropped from the top of a tower is equal to the acceleration due to gravity, which is approximately 9.8 m/s^2 downward. This acceleration remains constant as the stone falls towards the ground, neglecting air resistance.
What will happen to a stone dropped from the roof of a single story building to the surface of the earth?
The stone would fall straight down from the release point, it would fall with steadily increasing speed, and when it hit the ground, it would stop falling. The rate at which its speed increased during the fall would be 32.2 feet per second faster every second.
In shark tooth how do you get the paper?
It's on a stone building.
