IF it started out from rest, then V = a t = (7.8 x 30) = 234 meters per second
in the direction of the acceleration, at the end of 30 seconds.
-2.33 metres per second squared
Acceleration is a change in velocity per unit of time. Velocity is distance (d) per unit of time (t). That makes acceleration distance per unit of time squared, or something like this:We have distance/time2, or d/t2Distance is commonly measured in meters, and time in seconds. This makes acceleration appear in meters per second per second, or meters per second squared, or m/sec2.m/s2meters per second squared
No starting velocity was given, so I can't give a correct answer, but I can answer part of the question. Given an acceleration and a time through which an object accelerates, you can determine the change in velocity. Acceleration is just the change of velocity over a period of time. Since we have an acceleration of -3.1 meters per second squared, acting for two seconds, we have a change in velocity of -6.2 meters per second. Take the original velocity and subtract 6.2 meters per second to get the answer.
The change in the velocity divided by time in meters per second squared.
Use the formula for centripetal acceleration: velocity squared / radius.
Velocity can be measured in metres per second, not metres per second squared. Acceleration is measured in metres per second squared but knowing only the acceleration does not help in finding the velocity.
Acceleration occurs when velocity changes over time. The formula for it is as follows: a = (Vf - Vi) / t a: acceleration (meters/seconds2) Vf: Final velocity (meters/seconds) Vi: Initial Velocity (meters/seconds) t: Time (seconds)
-2.33 metres per second squared
The velocity gained by the aircraft in 4 seconds can be calculated using the formula: velocity = acceleration × time. Given acceleration of 3 m/s^2 and time of 4 seconds, the velocity gained by the aircraft would be 12 meters per second.
Velocity and acceleration are both vector quantities that describe motion. Velocity is the rate of change of an object's position over time, while acceleration is the rate of change of an object's velocity over time. In simpler terms, velocity tells us how fast an object is moving and in what direction, while acceleration tells us how quickly the velocity is changing, either by speeding up, slowing down, or changing direction.
Acceleration is a change in velocity per unit of time. Velocity is distance (d) per unit of time (t). That makes acceleration distance per unit of time squared, or something like this:We have distance/time2, or d/t2Distance is commonly measured in meters, and time in seconds. This makes acceleration appear in meters per second per second, or meters per second squared, or m/sec2.m/s2meters per second squared
For every second of acceleration the velocity is increased by that acceleration.
Acceleration is the change in velocity (m/s) divided by time (s), which is the same as meters divided by time in seconds squared (m/s2).
Meters/seconds squared
No starting velocity was given, so I can't give a correct answer, but I can answer part of the question. Given an acceleration and a time through which an object accelerates, you can determine the change in velocity. Acceleration is just the change of velocity over a period of time. Since we have an acceleration of -3.1 meters per second squared, acting for two seconds, we have a change in velocity of -6.2 meters per second. Take the original velocity and subtract 6.2 meters per second to get the answer.
The change in the velocity divided by time in meters per second squared.
Use the formula for centripetal acceleration: velocity squared / radius.