Vertex = (0,0)
Line of symmetry = y axis
You should of known that as this function is only X^2
It has y-axis symmetry. anyfunction with only x^2 and its coefficient has y-axis. These are called even fuctions. Therefore, it also might be called evensymmetry.
y = 3x2+2x-1 Line of symmetry: x = -1/3 Vertex coordinate: (-1/3, -4/3)
Forget about thw value of pi because it has nothing to do with the question. y = x2-8x+1 can be expressed as y = (x-4)2-15 Information about the vertex and line of symmetry can be extracted from the rearranged equation such as:- Vertex: (4, -15) Line of symmetry: x = 4
An isosceles triangle has one line of symmetry, which is drawn from the noncongruent side to the opposite vertex, and does not have a rotation symmetry.
From each vertex to its opposite vertex. These will be centered on a shared point at the center of the hexagon. Each complete line will be a line of symmetry for the hexagon.
A line of symmetry must go from one vertex to the midpoint of the opposite side.
In the form y = ax² + bx + c the axis of symmetry is given by the line x = -b/2a The axis of symmetry runs through the vertex, and the vertex is given by (-b/2a, -b²/4a + c). For y = 2x² + 4x - 10: → axis of symmetry is x = -4/(2×2) = -4/4 = -1 → vertex = (-1, -4²/(4×2) - 10) = (-1, -16/8 - 10) = (-1, -12)
It is (-1, 3).
K
2
How about y = (x - 2)2 = x2 - 4x + 4 ? That is the equation of a parabola whose axis of symmetry is the vertical line, x = 2. Its vertex is located at the point (2, 0).
y = (x-4)(x-4) * * * The factors above are shown correctly. The axis of symmetry is the vertical line passing through the vertex, which is the point located at (4, 0). The equation of that line is x = 4, which is the answer you requested.