The resistance of 1 mm (diameter) solid copper is about 21.8 ohms per kilometer.
That's 10.6 ohms in 500 meters.
When 230 mA flows through 10.6 ohms, the voltage drop is
I · R = (.230)x(10.6) = 2.438 volts.
The voltage of the supply is irrelevant.
This is a voltage drop question. To answer this question a voltage must be given.
It depends on the voltage that the motor needs, because a higher voltage requires less current for a given amount of power. Also a higher voltage can tolerate a higher voltage drop. So there are two things that lead to a thinner wire when the voltage is higher.
70mm 4core copper cable
Incorrectly calibrated meters.
Since you're only going 6 meters as your distance the voltage drop will not be a significant issue and you can use #12 AWG that is rated for 20 Amps
It is 1:500 scale.
Voltage can kill a person even if you are only meters away.
meters
any where across where you think there is voltage present
A meter is a unit of metric measurement. A square meter is like drawing 4 meters to make a square.
in the short circuit test we applied supply voltage on L.V side and short circuit the H.V side and connect the ammeter in H.V circuit to measure the short circuit current. with the help of s.c test we measure the copper losses in the transformers.
Not enough to worry about as long as your wire is sized properly to 40 amp. 6 meters isn't very long
A 2/0 AWG copper conductor will limit the voltage drop to 3% or less when supplying 65 amps for 150 metres on a 240 volt system.
To measure voltages and voltage drops
No. The speed of sound in copper is well below that.
It is usually required in electrical examinations to make calculations. Simple answer to a complicated calculation. Remember, take peak to peak voltage and multiply by .707, the result being average voltage. This is the voltage that electrical test meters read.
Draw a square with each side being 3m in length.