It looks as if you can use Ohm's Law to calculate this: V=IR (voltage = current x resistance).
Are we talking electricity here? And a meter for testing current flow? An ammeter measures the amount of current (in amperes) in a closed, powered electrical circuit. The formula, e=i*r (Voltage = current * resistance) when solved for i is i=e/r So if you have 120 volts flowing through a circuit that has a total resistance of 8 ohms, the current would equal 120 / 8 or 15 amperes. - wjs1632 -
There is no direct relation of electric current and power. In order to knowhow much power (or energy) the current gives up, you must know what thecurrent is flowing through.The easiest way to describe anything through which the current is flowing isto measure and state its electrical resistance.Once you know the resistance through which the current is flowing . . .Power delivered by the current = (magnitude of the current, amperes)2 x (resistance of the path, ohms)The power is delivered continuously. Its unit is watts.Each watt of power means 1 joule of energy every second.
10
There is insufficient information in the question to answer it. 30 volts generating 14 amperes means the two resistors have a total series resistance of 2.143 ohms. Since no relationship was stated, we don't know the value of the individual resistors. If the two resistors had the same resistance, the net parallel resistance would be 0.536 ohms, and a current of 56 amperes would flow.
Depends - in the real world as a resistor gets hotter (current flowing through it) its resistance increases.
amperes or A.
Are we talking electricity here? And a meter for testing current flow? An ammeter measures the amount of current (in amperes) in a closed, powered electrical circuit. The formula, e=i*r (Voltage = current * resistance) when solved for i is i=e/r So if you have 120 volts flowing through a circuit that has a total resistance of 8 ohms, the current would equal 120 / 8 or 15 amperes. - wjs1632 -
If the two 5 ohm resistors were in series, then the current would be 1.2 amperes. If they were in parallel, then the current would be 4.8 amperes. Ohm's Law: Current = Voltage divided by Resistance RSeries = Summation1toN RN RPARALLEL = 1 / Summation1toN (1 / RN)
One of Kierchieff's laws tell us that the more wattage (energy) consumed by an electrical device in a circuit, the larger the voltage difference that exists across the device and the greater the current flowing through it. The energy consumed is directly proportional to the Impedance of the electrical device but is more importantly proportional to the square of the current. WATTS=VOLTS X AMPERES= RESISTANCE (IMPEDANCE) X AMPERES X AMPERES A Circuit with Current but without resistance would exhibit no energy at all.
An ammeter measured how many amperes of current are flowing in an electrical circuit.
There is no direct relation of electric current and power. In order to knowhow much power (or energy) the current gives up, you must know what thecurrent is flowing through.The easiest way to describe anything through which the current is flowing isto measure and state its electrical resistance.Once you know the resistance through which the current is flowing . . .Power delivered by the current = (magnitude of the current, amperes)2 x (resistance of the path, ohms)The power is delivered continuously. Its unit is watts.Each watt of power means 1 joule of energy every second.
Resistance
When the current flowing in a circuit is very small the resistance will be very high.
Current flowing through a device depends on resistance offered by that device.
The current depends on the total effecvtive resistance of everything connectedacross the battery.If the resistor is the only component there, then the current is E/R = 12/3 = 4 amperes.
Voltage = Current * Resistance ANSWER: 1000V = 1000 I = 1000 Ohms does not compute It is a relationship that states if there is 1 ohm and 1 volt there will be =1 amperes flowing. The number can change but the relation ship will not
If you divide the charge by the time, you get the average current (in amperes).