Use Charles's Law: V1 / T1 = V2 / T2 Constant pressure must be kept. Absolute temp. must be used. T1 = 0 + 273 = 273 degr.K T2 = 200 + 273 = 473 degr.K 25 L / 273 K = V2 / 473 K V2 = 25 x 473 / 273 = 43.315 L (final volume).
turn 0 C to 273 K , 30 C to 303K then 255*85/303=101.3*V/273 V=193mL
In chemistry, K is 273+Degrees C.
288 plus 273 equals 561 K. (Any)degrees C +273 = degrees K
subtract 273 240-273 240o K=-33o C
You can use the formula pV = nRT, and since it's Standard Temperature and Pressure, p = 1 bar, T = 273 K. V = nRT/p = 2.2*0.08314*273/1 = 49.9 liters
Use Charles's Law: V1 / T1 = V2 / T2 Constant pressure must be kept. Absolute temp. must be used. T1 = 0 + 273 = 273 degr.K T2 = 200 + 273 = 473 degr.K 25 L / 273 K = V2 / 473 K V2 = 25 x 473 / 273 = 43.315 L (final volume).
C = K -273
The volume will be 5723 assuming that the balloon's elasticity makes no difference.
K= C + 273 Example- the freezing point of water is 0 c 0 + 273= 273. So water freezes at 273 k
Use general gas law: V = n.R.T / pin which:n = number of moles (to be filled in)R = gas constant = 8.20*10-2 (L.atm.K-1.mol-1)T = tempeature (K) = 273 K (stand.T)p = pressure (atm) = 1.00 atm (stand.P)then the calculated volume is in Liter
273
MM stands for 1,000 x 1,000 = 1,000,000 or million. Nm³ stands for normal cubic meter. One normal or standard cubic meter is the volume of 1 m³ at a temperature of 0 °C (273 K) and an absolute pressure of 1.01325 bar. So MMNm³ = million normal cubic meter gas.
You add 273: K = C + 273.
273 K (0° Celsius) and 1 ATM pressure
Kelvin is written with a non-negative number, then K. For example, 273 Kelvin is simply written 273 K.
turn 0 C to 273 K , 30 C to 303K then 255*85/303=101.3*V/273 V=193mL