8.96 cm3
211g of carbon dioxide are equal to 4,794 moles.
The volume occupied by 2.12 moles of nitrous oxide is 9.35. A mole is described in chemistry as an amount of pure substance containing the same number of chemical units as there are atoms.
This volume is 6,197 399 5 at 25 0C.
To determine the volume of carbon dioxide needed, you would need to know the stoichiometry of the reaction between carbon dioxide and calcium carbonate. In this case, since 20 grams of calcium carbonate is given, you would convert that to moles using the molar mass of calcium carbonate. Then, using the balanced equation, you can determine the mole ratio between carbon dioxide and calcium carbonate. Finally, using the molar volume of carbon dioxide gas at the given conditions (usually 22.4 L/mol at standard temperature and pressure), you can calculate the volume of carbon dioxide needed.
5
Moles of carbon dioxide = grams/amu of carbon dioxide. Moles = 19g/44amu Moles of carbon dioxide = .432
211g of carbon dioxide are equal to 4,794 moles.
2,22 1023 molecules of carbon dioxide is equal to 0,368 moles.
7.30 moles carbon dioxide (6.022 X 10^23/1 mole CO2) = 4.40 X 10^24 molecules of carbon dioxide
11L and 22mL
2.10 moles carbon dioxide (6.022 X 1023/1 mole CO2) = 1.26 X 1024 molecules of carbon dioxide ==============================
2.1 moles Carbon dioxide (6.022 X 1023/1 mole CO2) = 1.3 X 1024 molecules of carbon dioxide =============================
0.1 moles There is one carbon and two oxygens 1 x 0.1 = 0.1
3.74 moles CO2 (6.022 X 10^23/1mol CO2) = 2.25 X 10^24 molecules of carbon dioxide.
When methane undergoes complete combustion, the equation for the reaction is CH4 + 2 O2 -> CO2 + 2 H2O. This shows that the number of moles of carbon dioxide formed are the same as the number of moles of methane reacted, so that 14 moles of carbon dioxide will be formed from 14 moles of methane.
= 9403.41
6.23 mol carbon dioxide