5126 cm3
10 kg is mass = STP = 10 ltr volume
.01kg
1.76 grams CO2 (1 mole CO2/44.01 grams)(2 mole O/1 mole CO2)(6.022 X 10^23/1 mole O2) = 4.82 X 10^22 atoms of oxygen gas
grams is weight - cups is volume.
mass = density x volume Mass = 5 grams per centimeter cubed x 10 centimeters cubed = 50 grams
CaCO3 + 2HCl -> CaCl2 + CO2 +H2O
C + O2 ==> CO2At STP 1 mole CO2 = 22.4 L 10L x 1 mole/22.4 L = 0.446 moles CO2 needed 1 mole C = 1 mole CO2 Therefore you need 0.446 moles C grams C = 0.446 moles C x 12 g/mole = 5.36 grams = 5 g (to 1 significant figure)
10 kg is mass = STP = 10 ltr volume
The mass is 10 727 kg.
.01kg
After figuring out the calculations using the weight of CO2 and Avogadro's number, the total number of atoms in 110 grams of CO2 is 2.34 X 10^18 in sum.
The mass of 40 grams is 40 grams and the volume of 20mL is, wait for it, ... 20 mL!
1.76 grams CO2 (1 mole CO2/44.01 grams)(2 mole O/1 mole CO2)(6.022 X 10^23/1 mole O2) = 4.82 X 10^22 atoms of oxygen gas
Balanced equation. C7H16 + 11O2 >> 7CO2 + 8H2O 2.00 moles C7H16 (7moles CO2/1mole C7H16) = 14 moles CO2 ( I forget STP standard, so will use PV = nRT ) (1atm)(V) = (14moles CO2)(0.08206 Latm/molK)(273.15K) Volume CO2 = 14 *0.08206*273.15/1 = 314 Liters CO2
To find the volume of 10 grams of acetone, you use the fact that the density of acetone is 0.7857 grams per cubic centimeter. The density formula is given as mass divided by volume, or m/V. The volume is mass/density or 10/0.7857, which is equal to 12.73 cubic centimeter.
10 ml
The reaction is: 2 C2H2 + 5 O2 -------------- 4 CO2 + 2 H2O.