Not enough information. You would also have to know either the volume, or the density, of the object.
Volume = length x width x height... or aria times height
200 grams is equivalent to 7 ounces or just under a cup.
A U.S. quarter (25¢) weighs 0.2 ounces, or 5.7 grams. Therefore, 35 quarters would weigh approximately (just barely under) 200 grams. Canadian quarters weigh 0.18 ounces (5.1 grams), so you would need 40 of them to get to 200 grams.
It is called buoyant force. It is calculated by determining the volume of water displaced by the object, which is the volume of the object under water.The weight of this quantity of water is the buoyant force. It can also be calculated by knowing the depth of the object in the water, the pressure at that depth, and the area of the bottom of the object. Buoyant Force = Pressure * depth It can also be calculated by knowing the weight of the object. If an object is floating the water is supporting the object's weight. So the buoyant force = weight of object
3.125g (This is not correct)________________________Before you get shot for under weighing your pot. An 8th of an ounce is 3.5 grams. Well at least where I come from:)Good luck.Actually, since an ounce weighs 28.3495231 then an eighth would weigh 3.5436903875!
It depends on the density of the object that weighs one pound, and how much of it is under water. The object will weight 1lb - water density * object volume under water; If the object is on average is less dense the water (i.e. is buoyant), and is allowed to swim, its weight will be 0 because proportion of its volume under water will compensate gravity exactly.
If an object floats in water, we can immediately conclude that it is less dense than the water. So, we've already gained a bit of information. But can we learn more? Yes. We can further "ballpark" our estimate of the object's density through additional observation and deduction. About how much of the object is submerged? If, say, 75 percent of the object is under water, we can then say that its relative density -- that is, its specific gravity -- is about 0.75. In other words, it has a density of 0.75 grams per milliliter or, equivalently, 0.75 grams per cubic centimeter. (Note that the density of water is 1.00 gram per milliliter.) But can we do better? I think so. If we measure the volume of water displaced by the object when it is placed into the container of water, we can calculate the weight of the object, because its weight will be equal to the weight of the water it displaces. If the floating object displaces, say, 100 milliliters of water, then we know it weighs 100 grams, because, as noted above, the density of water is one gram per milliliter. But we're not done. To calculate an object's density, we must know its volume as well as its mass. From the measurement above, we know the object's weight , but we don't know its volume, mainly because of its irregular shape. But if we carefully push the object completely under water, it will displace an amount of water equal to its volume. Let's say that when we submerge the object fully, it displaces 130 milliliters of water. We therefore conclude that its volume is 130 milliliters, which is equal to 130 cubic centimeters. Since the object weighs 100 grams and has a volume of 130 cubic centimeters, its density is 100 grams/130 cubic centimeters = 0.769 g/cm3.
Simply because the volume of water displaced is not equal to the actual volume of the object. If an object is lighter than water, you have to find another method of determining its volume. ------------------------------------ alternatively you could use a very thin pin to push the object under the water. However, the volume of the submerged portion of the pin would need to be suvtracted from the volume of the object measured.
First pour water into the can until it overflows and drains. Next place an object into the overflow can, being careful not to spill. Place a beaker under the overflow can to collect the water that is displaced by the object. Record the volume in millimeters of the displaced water. This is the volume of the object.
Volume = length x width x height... or aria times height
Literal answer : 240 grams. A box with dimensions of 160 cm is just a line with no width nor height. For a box with a volume of 160 cm cubed : just subtract 160 from 240.
You can push it under water / under the liquid's surface, and measure the displacement of liquid.
Under normal conditions the volume would be 123.67 cubic centimeters as the density of water is 1 gm per cc
Metric units of volume include the cubic meter, cubic centimeter, cubic millimeter, milliliter, cubic kilometer, and liter. When used to express the volume of a space or object, the shape of the object is completely irrelevant.
An official (adult) ball weighs just under 1 pound (410 to 450 grams).
displacement - invented by Archimedes. Completely fill a large volume of something with water. Have a spout to channel all excess water. Place a graduated cylinder under the spout. Place irregular object in the large volume filled with water. The volume of the irregular object will displace an equivalent volume of water into the graduated cylinder. The measured volume in the cylinder is the volume of the irregular object.
4 quarters is approximately an ounce. one U S quarter weighs 5.67 grams which is almost exactly equal to 0.2 ounces. so five quarters equal 1 ounce try Google for stuff like this.