167 liters. Your welcome:)
"Normal" indicates that the volume is a calculated volume of the gas mass flow at standard temperature and pressure (STP). The current version of IUPAC's standard is a temperature of 0 °C (273.15 K, 32 °F) and an absolute pressure of 100 kPa (14.504 psi, 0.986 atm), while NIST's version is a temperature of 20 °C (293.15 K, 68 °F) and an absolute pressure of 101.325 kPa (14.696 psi, 1 atm). Once the specific SRTP conditions are determined the STP volume will have to be converted to the volume at conditions present at the location using the appropriate gas laws.
Boyle's Law states that in a closed system, the pressure of a gas times its volume is a constant. So, if pressure = P, volume = V, and k = a constant, then PV = k.
If a sample of an ideal gas has a volume of 2.22 at 287 K and 1.13 atm what will the pressure be when the volume is 1.47 L and the temperature is 306 K?
The volume is 0,82 L.
A bottle of compressed gas. The K references a specific wet volume of 49.9L. Other std sizes can be found on the related link.This term can also refer to a vial (bottle) of the (mostly veterinary) anesthetic Ketamine.
1 K, or Kilo, is 1,000. So, dividing 1500 by 1000 = 1.5 K.
If you mean what means does one have to measure it, the best tool is "displacement": You take a known volume of water, and immerse the thing you want to measure. The amount of extra space the water takes up will be exactly the volume of the thing you put in it.
The wiring is different. You need an 89+
Depends on the available pressure If you have 60 PSI coming into a structure then you will get 60 PSI out of the sprinkler Just look at the "K" factoring for friction losses
Yes. Both MYs used the same transmissions - NV3500 (manual) or 4L60E (auto).
If I remember correctly: K= 4 Wheel drive C = 2 Wheel drive
It means 1.5 thousand ("k" means thousand) or 1500.
about 1500 yards
K. Glamann has written: 'European trade, 1500-1750'
167 liters. Your welcome:)
8.51 g/l at standard temperature (0 degrees Celsius,) but 7.93 g/l at room temperature (20 degrees Celsius). 1.251 g/l * 1 ATM / (100 psi * .0680459639 ATM/psi) = 8.51 g/l 1.251 g/l * 1 ATM / (100 psi * .0680459639 ATM/psi) / (293 K / 273 K) = 7.93 g/l