The same as it would be for anything from air to uranium occupying a volume of 8 x 3 x 3: It would be: 72.
The equation for the volume of a rectangular prism (such as a block of ice) is height times width times depth. That would make the volume of this block of ice is 9 meters cubed.
3x1.5x2=9 meters3
1 Steel Ruler 2 Measuring Tape 3 Yardstick
The Volume of steel used should always be less than the volume of ship made out of it.The ratio could differ and hence there may be no specific ratio.The greater the (Ratio of Volume of ship:Ratio of Volume of steel used) say 3:1that means the ship can carry about 2 times the volume of the steel used.That means the water displaced would be 3 times volume of steel hence the water is applying the force on ship is 3 times weight of steel.***STUDY BUOYANCY
The volume of a 8inx8inx16in block is 1024in^3 or .59259ft^3. I would assume that steel is used for the reinforcing. The density of steel varies from 484 to 503 lb/ft^3 and the density of concrete varies from 109.25 to 149.83 lb/ft^3. So assuming that the steel reinforcement accounts for 6% of the volume then the weight of the steel would be greater than 17.21lbs (.59259ft^3*0.06*484lb/ft^3) and less than 17.88lbs (.59259ft^3*0.06*503lb/ft^3). The concrete would then account for 94% of the volume and its weight would be greater than 60.86lbs (.59259ft^3*0.94*109.25lb/ft^3) and less than 83.46lbs (.59259ft^3*0.94*149.83lb/ft^3). So with all of these assumptions the block would weigh between 78.07 and 101.34lbs.
Quarts, liters, bushels.
The volume is 27 inches
Length multiplied by Width Multiplied by Height 3 x 1.5 x 2 = 9
It is: 3*3*3 = 27 cubic cm
A block has a mass of 550 g and a volume of 650 cm 3 . What is the block's density, and will it sink or float in freshwater?
A measuring tape made of fiberglass. I have 3, very smooth and much better than steel tapes.
400 cm 3