Want this question answered?
Frequency = (speed) divided by (wavelength) = (330) / (15) = 22 Hz.
How much time would it take for the sound of thunder to travel 2000 meters if sound travels a speed of 330 meters per sec.
Simply using the formula wavelength = velocity of the wave / frequency we can get the required. So we need velocity of sound wave. Usually we take it to be 330 m/s at room temperature. Now using 330 and 21 we can get wavelength in metre
If sound travels at a speed of 330 miles per second, that's equivalent to about1,188,000 miles per hour, and it takes the sound of thunder 0.002824 secondto travel 1,500 meters.But it doesn't. In order to arrive at a reasonable solution, we need to get ourconstants straight. The speed of sound is not 330 miles per second. It's morelike 330 meters per second.1,500/330 = 4.545 seconds.(rounded)
Use the formula: Velocity= Wavelength*Frequency 330=5*fequency frequency=330/5 frequency=66
Frequency = (speed) divided by (wavelength) = (330) / (15) = 22 Hz.
Speed of sound depends on the density of the medium in which it travels. In air medium, speed of sound wave is approximately 330 m/s.
330/20 = 16' 6"
The total distance traveled by the sound wave is 2 m. At a rate of 330 m/s, it will take 0.00606 seconds for the bat to hear the echo.
1082.677 ft
330 miles / 5.5 hours = 60 mph
If a car travels 330 miles in 5.5 hours, what is the mph?
How much time would it take for the sound of thunder to travel 2000 meters if sound travels a speed of 330 meters per sec.
It travels 100 miles in 2.5 hours.
Simply using the formula wavelength = velocity of the wave / frequency we can get the required. So we need velocity of sound wave. Usually we take it to be 330 m/s at room temperature. Now using 330 and 21 we can get wavelength in metre
Radio wave travel faster than sound wave. Radio wave is the same as light wave except at different wavelength. It travel at speed of light (3 x 108 m/s). Sound wave travel at only 330 m/s and probably can go up to 3,300 m/s in solid medium which is far slower than the speed of light.
Since the minor arc is 30 degrees, the major arc is 330 degrees (360 - 30). So we have: 330 degrees : arc length 10 30 degrees : arc length x 330/30 = 10/x 11/1 = 10/x x = 10/11 x = 0.9 approximately So the length of the minor arc is approximately 0.9 units.