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CuSO4(aq)+ 2NaOH(aq) --> Cu(OH)2(ppt) + Na2SO4(aq)

Or the more complex formula ignoring the spectator ions Na+ and SO42-

[Cu(H20)6]2+ + OH- --> [Cu(H20)4(OH)2] + H20

Note: [Cu(H20)6]2+ is the form Cu2+ ions exist in an aqueous solution

written by msp 96

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13y ago
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15y ago

Are you looking for copper and sodium hydroxide or copper nitrate and sodium hydroxide? Copper nitarte and sodium hydroxide is Cu(NO3)2(aq) + 2 NaOH(aq) --> Cu(OH)2(s) + 2 NaNO3(aq) Otherwise I guess the equation would be a single replacement of Cu(s) + 2NaOH(aq) -->Cu(OH)2 (aq) + 2Na(s), if your using copper II. With those to products, if they react, that is what you get, but I'm not sure that they would react without a catalyst. Hope that helps.

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15y ago

Copper (II) Hydroxide (Cupric hydroxide): Cu(OH)2 Sodium Sulfate: Na2SO4

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13y ago

I think it's

2NaOH (aq) + CuSO4 (aq) = Na2SO4 (aq) + Cu(OH)2 (s)

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15y ago

==>Na2CO3 + CuSO4 Na2SO4 + CuCO3

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Q: Equation for the addition of sodium carbonate solution to copper sulphate solution?
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