Silver oxide --> silver and (+) oxygen
Ag2O --> Ag2 + O2
BALANCED =
2Ag2O --> 2Ag2 + O2
Silver plus oxygen yields silver oxide. Ag + O2 --> Ag2O
(Zn)s + 2(Ag+)aq --> (Zn2+)aq + 2(Ag)s
Nitrate is tribune ion in this intern electrolysis
2Ag + Cl2 --> 2AgCl
1421
Ag+O=AgO
Ag + Cl (silver and chlorine) i'd guess
Barium reacts with halogens, (fluorine, chlorine, bromine, and iodine), and oxygen. It also reacts with oxidizing agents, such as potassium chlorate, and acids such as sulfuric acid and nitric acid.
When the light hits silver chloride it loses electrons and becomes metal and chlorine, so the result would be low.
balanced equation:- AgNO3(aq) + HBr(aq) ----> AgBr(s) + HNO3(aq)
AgBr + (NH3)2SO4
87
AgCl It always has a valency of +1, though it is a transition metal
This equation is 3 BaCl2 + 2 Ag3PO4 -> Ba3(PO4)2 + 6 AgCl.
KCl+Ag(NO3)--ARROW- AgCl+(KNO3)
To determine the mass of silver chloride produced, we need to know the balanced chemical equation for the reaction between silver nitrate (AgNO3) and sodium chloride (NaCl) that produces silver chloride (AgCl) as a precipitate. Once we have the balanced equation, we can use the stoichiometry of the reaction to determine the number of moles of AgCl produced, and then convert that to mass using the molar mass of AgCl.
Silver and chlorine
NH4Cl (aq) + AgNO3 (aq) => AgCl (s) + NH4NO3 (aq).
Silver and Chlorine
Silver chloride is easily synthesized by combining aqueous solutions of silver nitrate and sodium chloride.
Ag+ + Cl- = AgCl So, it's correct.
the chemical equation for beryllium chloride reacts with silver nitrate in water to form beryllium nitrate and silver chloride can be written as follows .BeCl2 +2 Ag NO3 -> Be (NO3) 2 +2AgCl.A balanced equation has equal numbers of each type of atom on each side of the equation.
No reaction