Latitude
· Yellow Jacket
At what angle should a vector be directed to so that its x component is equal to its y component
Yes: such a vector would have only an x component, and it's change in regards to the y axis would be 0 (i.e. it would never get closer or farther from the y-axis).
The part of a vector that lies along an axis is called the "component" of the vector. Each component represents the projection of the vector onto the respective axis, usually denoted as the x-component, y-component, and z-component in three-dimensional space. These components are crucial for analyzing the vector's behavior in different directions.
You have a right triangle and can use trig. Degree mode. tan(theta) = adjacent/opposite( y component ) tan( 60 degrees) = (5 m/s)/(y comp.) y component = 5 m/s)/(tan 60 degrees) = 2.887 m/s ( you can call it 3 m/s ) -----------------------------------------------
· Yellow Jacket · Yorkshire Terrier
Yes.
0 N, since there is no x component of the force.
The component of a vector x perpendicular to the vector y is x*y*sin(A) where A is the angle between the two vectors.
Force is only acting on x axis so y component is actually 0
Yellowcake (a Uranium bearing rock).
The y component of a vector can be found using the sine ratio since: sin θ = opp/hyp = y-component/magnitude → y-component = magnitude × sin(angle_of_vector) The y-component of the resultant vector is the sum of the y-components of each of the vectors: v1: y1 = 4 × sin 15° v2: y2 = 9 × sin 350° → v = v1 + v2: y = y1 + y2 = 4 sin 15° + 9 sin 350° ≈ −0.528