Let's see:
It is a universal constant, that is, it is the same for every corner of the universe ( remains 6.67×10 to the negative eleventh power )!
It is not to be confused with g. That is, the acceleration due to gravity on the earth. g is a derivative of the G.
It is dimensionless; it doesn't have a unit. In simpler terms, it's a plain number.
The value of universal gravitational Constant(G) doesn't change it is constant at any place in the universe, it's value is 6.67259 x 10-11Nm2/Kg2 But the value of g varies from from place to place on earth,planet to planet and star to star because g=GM/R2 As G is constant g depends on M=mass of planet,R=radius of planet,so g varies with the change in M and R.
In a theoretical scenario with constant velocity, the true acceleration would typically be zero.
The gravitational constant, denoted as G, is considered to be a constant value in physics. It is a fundamental constant that is believed to remain the same over time and across the universe.
G would remain the same, it's the gravitational constant which is the same everywhere in the universe. g would increase by 4 times, assuming that the radius of the earth didn't increase.
True. The particles that make up matter are in constant motion due to their kinetic energy. This motion can vary in speed and direction depending on factors such as temperature and pressure.
Cavendish measured the gravitational constant "G".
g, the force of the Earth's gravitational attraction, is not a constant.
G is called The universal gravitational constant because at any point of the universe the value of G is constant. G=6.67*10^-11 N m^2/kg^2...!!!!1
There is no evidence to suggest that the gravitational constant 'G' is not the exact same number everywhere in the universe.
Yes, it is true that an equilibrium constant is not changed by a change in pressure.
The value of universal gravitational Constant(G) doesn't change it is constant at any place in the universe, it's value is 6.67259 x 10-11Nm2/Kg2 But the value of g varies from from place to place on earth,planet to planet and star to star because g=GM/R2 As G is constant g depends on M=mass of planet,R=radius of planet,so g varies with the change in M and R.
The relationship between the Delta G equation and the equilibrium constant (Keq) is that they are related through the equation: G -RT ln(Keq). This equation shows how the change in Gibbs free energy (G) is related to the equilibrium constant (Keq) at a given temperature (T) and the gas constant (R).
To determine the equilibrium constant from the change in Gibbs free energy (G), you can use the equation G -RT ln(K), where G is the change in Gibbs free energy, R is the gas constant, T is the temperature in Kelvin, ln is the natural logarithm, and K is the equilibrium constant. By rearranging this equation, you can solve for K to find the equilibrium constant.
I think that g (the gravitational constant) varies dependent on your proximity to other massive bodies. For example the value of g on the moon is less than the value of g on earth. It is not constant throughout the universe.
independent variable
No, it is not true.
To calculate the equilibrium constant from the change in Gibbs free energy (G), you can use the equation: G -RT ln(K), where G is the change in Gibbs free energy, R is the gas constant, T is the temperature in Kelvin, ln is the natural logarithm, and K is the equilibrium constant. By rearranging this equation, you can solve for K as K e(-G/RT).