Varchar in SQL means string in PHP.
To print a particular value in PHP you have to select which variable you wish to print. Below is an example of how this can be done. <?php $var[1] = "Hello"; $var[2] = "Lalala"; print $var[2]; // prints Lalala but not Hello ?>
isset( $var ) is a PHP function which returns TRUE or FALSE depending on whether a specified $var has been assigned to any value (or, initialized).
An array in C is basically a pointer to a sequence of successive elements of the array type; for example this array char var[4]; is an array of four characters. In this case "var" will be a pointer to character, or char*, on a system with a 32-bit memory space (all PCs from the 386 up to the year 2008, newer may have a larger memory space) "var" itself will be 32 bits in size. The first array value is the char-sized (assume 8 bits) memory location where "var" is pointing to; this is "*var" or "var[0]". The second element of the array is "*(var+1*sizeof(char))" or "var[1]", the third "*(var+2*sizeof(char))" or "var[2]" and the fourth is "*(var+3*sizeof(char))" or "var[3]". because C has no boundary checking trying to write of read "var[4]" (the fifth char) will not rise a violation, however you never requested this memory space! The compiler may very well have decided to put another variable in this place, which will thus be overwritten when writing to it. This is why you should ALWAYS assure that there is no way you could ever write outside of the reserved memory space! To sum up: int var[SIZE]; will reserve SIZE slots of "int"-sized memory and a pointer to the first of those ints. "var" is that pointer, while "var[0]" is the first int. Assure to never write (or read) to var[X] where X is EQUAL or greater than SIZE (or X less than zero).
A double dollar sign in php makes a variable with a name equal to the value of the original variable. It works like this:$var = "keith";$$var = "palmer";print ($keith);// The output is: palmer
To pass PHP Variable value in Jquery simpley echo that variable : Eg <script> var jQueryVariable=<?php echo $anyVariable?> </script>
The money sine ($) denotes a variable in PHP; for example: $var = 'foobar'; It can also be used to reference an array, object, any of the othe typical things that can be assigned to a variable.
int scanf(char* format, ...); the format accepts the format specifier string, the elipsis operator accepts the variable list scanf("var type var type ...", &var, &var, ...); example: int num1, num2, num3; scanf("%d %d %d",&num1,&num2,&num3); Is that what you were looking for? Maybe this can help also...
Yes. It can be done like so: class myClass{ var $foo; function __construct($bar){ $this->foo = $bar; } }
Use the substr function. For example <?php $name= "naruto uzumaki"; echo substr($name, 0, 6) ; // The first six char are taken by this code ?> This will output naruto
A typeless variable is one which is not bound to a specific data type. This variable can contain a string, then be assigned an integer, then an array, then an object, etc. Note that some programming languages, like the C languages, do not offer typeless variables.An example of PHP typeless variables in action:
That depends on what language you're using. In PHP for example, it would be like this: $c = chr($i); In C, it would be: char c = (char)i; in BASIC, you'd use: LET C$ = CHR$(I)
PHP provides a function called empty($var), which tests if $var is "empty." Empty has an odd definition, since the function returns true if the variable loosely equates to False. Although a zero-length string would be considered empty, so would the string "0" (among other irrelevant values).To accept the value "0" from a field, use strlen($var). It tests the length of any variable, after casting it to a string. If this function truly equals integer zero (compared with triple-equals), the variable must be empty.