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A: Vce is the voltage across the transistor . Ie is the emitter current. Ico is the collector current with the base open. Or really the leakage.
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What is the correct current equation for a bipolar junction transistor?
Ie=Ic+Ib
What is the average VCE Enter Score?
53.95 is the average ENTER score for VCE students
Find the base current in a transistor when the collector current is 10mA and the emmiter current is 10.1mA?
IB=IE-IC =100uA
What is Si transistor?
A silicon transistor is a transistor made of silicon.
How do you connect the led through 8051 micro controller?
Generally the output pin of the MCU will be, between 4.3V and 5V when high and will allow a maximum current of 15mA, an LED will have a volt drop of about 2 volt in forward bias conditions at 10mA which is about the minimum current to make it glow normally. Place a resistor in series with the MCU pin and the LED, connect the cathode pin of the LED to the ground. As an on state is created on the MCU, the current will flow through the resistor to the LED, through the anode, flow through the LED to the ground The minimum current for LED at the minimum voltage is must be used to obtain the Rs Rs=(Vmcumin-Vled)/Imin Rs=(4.3V-2V)/0.01A = 230R using a higer value 330R should be fine Imcu = (5V- 2V) / 330R = 9.1mA it should be safe for your MCU and it should produce a visible indication. I will not recommend making it to bright, LEDs can easily go to about 20mA but for most applications around 10mA is enough If one would need to use 15mA or more, then the help of an external transistor is recommended. Then you have VCC going through resistor Rs through LED Anode to Cathode to the collector of a NPN BJT transistor. Then from the Emitter to the ground. From the MCU let the voltage go though resistor Ri to the Base of the transistor. Generally it is bad to switch loads this way, since the loads are never properly grounded and said to be floating, but for LED it is ideal. Then Rs = (VCC-Vled-Vce) / Iled = (5V-2V-0.2V)/0.01A = 280R NAV = 330R Ic = (Vcc-Vled-Vce)/Rs = (5V-2V-0.2V)/330R = 8.47mA then ib = Ic/Beta = 8.47/100 = 84.8uA to allow some tolerance let Ibnew = Ib x 10 = 848uA Ri = (Vmcumin - Vbe)/Ibnew = (4.3V-0.7V)/848uA = 4.245K NAV = 4k7 The transistor: Ie= (Vmcumax-Vbe)/Ri = (5V-0.7V)/4.7k = 915uA Power dissipation for transistor is Pd= Vce x Ie = 0.2V x (Ib + Ic) =0.2 x 0.009395 = 1.88mW one can see, a very small transistor is required.
When an NPN transistor is saturated its Vce?
is zero
How do you find ic and vce for a base-biased npn transistor?
Uh dun't nuh
What should be the value of Vce if the base terminal of a transistor is open?
It would be zero because there is a leakage.
Gm of a transistor is proportional to?
Gm of a transistor is proportional to Ie/Vt. That is, emitter current divided by thermal voltage.
What is the correct current equation for a bipolar junction transistor?
Ie=Ic+Ib
What does vce stand for?
VCE stands for Victorian Certificate of Education.
Where does whine go under vvc vcc vc vce?
vce
What is the average VCE Enter Score?
53.95 is the average ENTER score for VCE students
What is the purpose of a heat sink in transistors?
Heat sinks are needed for transistors passing large currents. Waste heat is produced in transistors due to the current flowing through them. If you find that a transistor is becoming too hot to touch it certainly needs a heat sink! The heat sink helps to dissipate the heat by transferring it to the surrounding air. The rate of producing waste heat is called the thermal power, P. Usually the base current IB is too small to contribute much heat, so the thermal power is determined by the collector current IC and the voltage VCE across the transistor: P = IC × VCE The heat is not a problem if IC is small or if the transistor is used as a switch because when 'full on' VCE is almost zero. However, power transistors used in circuits such as an audio amplifier or a motor speed controller will be partly on most of the time and VCE may be about half the supply voltage. These power transistors will almost certainly need a heat sink to prevent them overheating. Power transistors usually have bolt holes for attaching heat sinks, but clip-on heat sinks are also available. Make sure you use the right type for your transistor. Many transistors have metal cases which are connected to one of their leads so it may be necessary to insulate the heat sink from the transistor. Insulating kits are available with a mica sheet and a plastic sleeve for the bolt. Heat-conducting paste can be used to improve heat flow from the transistor to the heat sink, this is especially important if an insulation kit is used.
How do you open VCE file or to run in on window 7?
To open and run VCE files on Windows 7 you need software known as Visual CertExam. This software is used to simulate VCE exams.
Find the base current in a transistor when the collector current is 10mA and the emmiter current is 10.1mA?
IB=IE-IC =100uA
What dc load line?
well, this is very simple to understand ,the DC load line of a circuit is nothing but the Kirchoff's voltage law on the out put circuit of the transistor-amplifier. As the KVL is linear equation involving voltage drops the equation of load line is a straight linelet us assume that the transistor is in CE configuration.VCC-VCE-ICRC=0vICRC=VCC-VCE of the form by=aX+c which is in the form of a straight line with positive intercepts on X(VCC) and Y(VCC / RC) axis and a negative slopewhere,x= VCE/RCy= ICm(slope)= -VCC/RC
