A: Vce is the voltage across the transistor . Ie is the emitter current. Ico is the collector current with the base open. Or really the leakage.
If the base terminal of a transistor is open, the transistor will be in an off state, meaning it is not conducting. In this condition, the collector-emitter voltage (Vce) would be expected to be approximately equal to the supply voltage, as there is no current flow through the collector-emitter path. Hence, Vce would be close to the maximum supply voltage applied to the collector.
Ie=Ic+Ib
53.95 is the average ENTER score for VCE students
IB=IE-IC =100uA
A silicon transistor is a transistor made of silicon.
is zero
Uh dun't nuh
It would be zero because there is a leakage.
Gm of a transistor is proportional to Ie/Vt. That is, emitter current divided by thermal voltage.
Ie=Ic+Ib
VCE stands for Victorian Certificate of Education.
vce
53.95 is the average ENTER score for VCE students
To open and run VCE files on Windows 7 you need software known as Visual CertExam. This software is used to simulate VCE exams.
IB=IE-IC =100uA
well, this is very simple to understand ,the DC load line of a circuit is nothing but the Kirchoff's voltage law on the out put circuit of the transistor-amplifier. As the KVL is linear equation involving voltage drops the equation of load line is a straight linelet us assume that the transistor is in CE configuration.VCC-VCE-ICRC=0vICRC=VCC-VCE of the form by=aX+c which is in the form of a straight line with positive intercepts on X(VCC) and Y(VCC / RC) axis and a negative slopewhere,x= VCE/RCy= ICm(slope)= -VCC/RC
# parameter are usually the base current ib,collector current ic,emitter current ie,collector emitter voltagevce,base emitter voltagevbe,collector base voltagevcb which decide the operation &output of the transistor