About 160 psi or 11 atm
Pressure depends on fluid depth, density, g, and surface pressure; not upon the volume.P at depth x = P0 + ( x ) ( density ) ( g )For P0 = 101000 Pa and d = 1025 kg per m^3 :P lake = ( 101000 N/m^2 ) + ( 7 m ) ( 1025 kg/m^3 ) ( 9.807 m/s^2 )P lake = ( 101000 N/m^2 ) + ( 70365 N/m^2 ) = 171365 N/m^2 = 171365 Pa
The greater the depth the greater the pressure.
The pressure at the same depth in any container doesn't depend on the size of the container. The pressure one meter below the surface is the same in a pond, a lake, a swimming pool, the middle of the Pacific Ocean, or a bath-tub.
its apparent depth is 1.5m.
About 160 psi or 11 atm
water pressure at the base of the dam is (specific weight of water * depth)2158.2KN/m2
Density of liquid (kg/m3) * gravitational constant (m/s2) * depth (m) = (extra) pressure under liquid (Pa) Density of water = 998 (kg/m3) gravitational constant = 9.81 (m/s2) 1,000 ATM = 1.013*10-5 Pa Raw formula: pressure under water = 1 (ATM) per 10 (m) depth
10 m depth is 2 bar pressure.
For your safety
Pressure depends on fluid depth, density, g, and surface pressure; not upon the volume.P at depth x = P0 + ( x ) ( density ) ( g )For P0 = 101000 Pa and d = 1025 kg per m^3 :P lake = ( 101000 N/m^2 ) + ( 7 m ) ( 1025 kg/m^3 ) ( 9.807 m/s^2 )P lake = ( 101000 N/m^2 ) + ( 70365 N/m^2 ) = 171365 N/m^2 = 171365 Pa
The greater the depth the greater the pressure.
The pressure at the same depth in any container doesn't depend on the size of the container. The pressure one meter below the surface is the same in a pond, a lake, a swimming pool, the middle of the Pacific Ocean, or a bath-tub.
Depth of 1.5-2 m
its apparent depth is 1.5m.
F = m * a Pressure at depth = force (newtons) / area (square metres) But> Force = mass of water * acceleration due to gravity
Pressure is calculated using P2=P1+pgh, where p is the density of the fluid (999.997kg/m^3), g is the acceleration of gravity (9.81m/s^2), and h is the depth you are trying to find the pressure at (in this case 1.2m). Absolute pressure is going to be atmospheric pressure (P1=101.3kPa) plus the relative pressure to the liquid surface. Thus we get P2=101300Pa+(999.997kg/m^3*9.81m /s^2*1.2m)=101300Pa+11772Pa=113124.9Pa or 16.4psi. Relative pressure is 11772Pa or 1.107psi. Hope this helps you out as well as shows how to calculate pressure at depth for other fluids at various depths. Regards, - Felix