The current value is 376.73 Ohms. For practical purposes, 120 x pi suffices.
There are separate values for the electrical and the magnetic components.
If the Ampere is redefined in 2015, this value will change.
The opening angle of a pyramidal horn antenna is to match the impedance of the horn antenna to that of free space. With this enlargement of the dimension, the velocity of the wave travelling will decrease. This will increase the guide wavelength, which in turn increases the impedance of the horn. This gives an impedance value closer to that of free space there by giving better power transfer.
377 ohms OR 120pie
The space wave is the wave that propagates directly through free space, rather than via some other object or medium like the ground.
Electical impedance of air is just under 377 Ohms. It depends on humidity and other factors. Dry air is close to free space. Scroll down to related links and look at "Characteristic impedance of free space ".
Wavelength = 1/Frequency
'Why' is not a science question. Answer2: Space is not empty. Space has resistance z = 375 Ohms which is related to Planck's Constant. Space contains electric C and magnetic W charge, such that h= CW and z = W/C. C = 4/3 atto Coulombs and W = 500 atto Webers. Answer 3: Space does not have resistance and does not contain electric charge, and there is no such thing as magnetic charge. Charged bodies and other matter can exist in space, otherwise space is empty. When an electromagnetic wave travels through, the wave is carried in electric and magnetic fields. The free-space wave impedance is equal to mu0 * c, where mu0 is the permeability of free space, 4pi*10**(-7) H/m and c is the speed of light 2.99792458E8 m/s (it is not related to Planck's constant). How can free-space have an impedance when it is empty? what the impedance really is is the ratio between the electric and magnetic field intensities, so when the fields are there it isn't empty, it's got the fields in :) Answer 4: It may sound like a lousy explanation, but it is possible because there is no reason for it not to be possible. Alternating magnetic and electric fields can propagate according to Maxwell, and there is no reason to believe they need any medium (except maybe analogy with sound). allow me to add to this answer. the previous writer tried describing this in how light may travel as a wave through space, but lets remember that electromagnetic radiation, which is light, has a duel nature as both a wave and a particle either called photons or quanta. photons which are particles can flow through space just like meteors can, which needs no medium, in fact, its easier for light to travel through space because there is nothing that can get in the photons way.
The average electric energy density of a plane electromagnetic wave traveling in vacuum is equal to the average of the square of the electric field strength divided by twice the characteristic impedance of free space (377 ohms). Mathematically, it is given by (ε₀ * E₀²)/2, where ε₀ is the permittivity of free space and E₀ is the magnitude of the electric field strength.
The characteristic impedance of a transmission line is the ratio of voltage to current of the propagating electrical wave. The line input impedance is the result of the superposition of forward and reverse, or reflected waves when the terminating impedance is not adapted. If the line is infinite, nothing returns from its end and only the forward wave exits. The voltage to current ratio is then the line characteristic impedance. Remark that the same occurs when the line is terminated by its characteristic impedance, the forward wave finds a perfect continuity to the load and no energy is reflected back to the line. A matched line is like an infinite line when looked from the input terminals. Long real lossy lines also act as infinite lines for the energy of the reflected wave is dissipated along the line before reaching the source.
A: As cable lenght increases the impedance changes with frequency especially at half wave lenght where at some frequency the impedance can be zero. The impedance is a function of capacitance inductance and resistance in the cable
For a voltage standing wave ratio (VSWR) of 1.0, the source impedance, load impedance, and transmission line characteristic impedance must be matched. To calculate actual VSWR, you need to know these three values. You're question only supplies one (50 ohm line). Review wikipedia's writeup on "standing wave ratio" to glean an understanding of what you're asking about.
Because "Empty space" is not empty. Maxwell believed in an Aether that propagted the radiation. This Aether exists as the free space impedance z=375 ohms. This impedance is related to Planck's Constant h=QWb and z=Wb/Q. Q and Wb are the Quantum Electric Charge Q=4/3 E-18 Coulombs and Wb =500E-18 Quantum magnetic Charge in Webers (Volt second). Q is the Photon Charge and is Quark Q=(13U,1d).
No, impedance inversion cannot be achieved with a short circuit stub. A short circuit stub will have a low impedance at the point where it is connected, which will not invert the impedance at that point. Impedance inversion can be achieved using techniques such as a quarter-wave transformer or a transmission line with specific impedance characteristics.