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What is the width of a peice of paper in millimeters and centimeters?
If you take the standard piece of paper as having a width of 8.5 inches, then the conversion to cm and mm is as follows:8.5 inch x 2.5 cm/inch = 21.25 cm21.25 cm x 10 mm/cm = 212.5 mm
What is the blocks density if the mass is 146 grams?
Density = mass / volume.Density = 146 g /[ height(cm) * length(cm) *width(cm)].
What is 1 quarter of 13 inches in cm?
1 inch = 2.54cm 13 inch = 2.54*13 cm or 33.02cm 1/4 of that is 8.255cm or 82.55mm or 1 quarter of 13 inches is 3.25inch Now 3.25in * 2.54 to get cm ... and it is 8.255cm again ;-)
Would you mesure the width of your pinkie with cm km m mm?
milimetres.
An aquarium has dimensions of 110.0 cm length 50.0 cm width and is 35.0 cm high what is the mass of the water that fills this aquarium?
192.5 liters or 50.85 gallons
How big is 2.2 cm?
22 cm is approximately 8 and three quarter inches.
How long is a .25 of an inch?
One quarter of an inch (0.25 in) is about the width of a #2 pencil (0.635 cm).
What is the width of quarter?
The width of a quarter is 24mm ( millimeters)
What is the width of a quarter?
The width of a quarter is 24mm ( millimeters)
Width of this page mm or cm?
what is the width of a page in mm or cm
The width of a rectangle is 2 cm less than 7 times the lenght the perimeter is 60 cm find the width and length?
The length is 4 cm, the width is 26 cm.
What is the width of a rectangle with length 14 cm in an area of 161 cm²?
Its width is: 161/14 = 11.5 cm
If the length of a rectangle is 3 cm longer than twice the width and that the perimeter of the rectangle is 90 cm then what is the width and the length?
the width equals 14 cm. and the length equals 31 cm.
What is the width of a rectangle with an area of 34cm2 and length of 9 cm?
Area = length x width ⇒ width = Area ÷ length = 34 cm2 ÷ 9 cm = 37/9 cm ~= 3.78 cm
What is the area of a rectangle with the length of 45 cm and a width of 30 cm?
The area of a rectangle is: length * width= 45 cm * 30 cm = 1350 cm^2
What is the area of a rectangle with a perimeter of 16cm?
Any area you want greater than 0 cm2 and less than or equal to 16 cm2. perimeter_of_rectangle = 2 x (width + length) 16 cm = 2 x (width + length) ⇒ width + length = 8 cm ⇒ length = 8 cm - width Neither dimension can be negative, so they are both greater than 0 cm and less than 8 cm. Area_of_rectangle = width x length ⇒ area = width x (8 cm - width) = 8 x width - width2 cm2 This has a minimum value when width = 0 cm or 8cm of 0 cm2, so the area of the perimeter must be greater than 0 cm2 (as the width can be neither 0 cm nor 8 cm). This has a maximum value when width = 4 cm: max_area = 8 x 4 - 42 cm2 = 16 cm2. when the width is between 0 cm and 4 cm (and so the length is between 8 cm and 4 cm) the area is between 0 cm2 and 16 cm2 When the width = 4 cm, the length is also 4 cm, that is the rectangle is a square.
What is the width of a rectangle that has a length of 48Cm and a diagonal of 50 Cm?
Width would be 14 cm
