(x2-7x+12)/(x2-2x-3)
factor the numerator & denominator:
(x-4)(x-3)/(x-3)(x-1)
now reduce:
(x-4)(x-3)/(x+1)(x-3)
(x-4)/(x+1)
(x - 5)(x + 12)
Let square = [x] -4+3*(-2)*[-4]+[3x-2x]=-4-6-2+[x]=-12+[x]The answer is negative 12 plus squared x.
x2 + x - 12 = (x + 4) (x - 3)
X2+5x-6. a=1, b=5, and c=-6 The formula is: -b plus or minus the square root of b squared minus 4ac all over 2a. -b+square root of b2-4ac ---- 2a -5 plus or minus the square root of 5 squared minus 4(1)(-6) -5 plus or minus the square root of 25-4(-6) -5 plus or minus the square root of 25+24 -5 plus or minus the square root of 49 -5 plus or minus 7 Here is where you split into two different answers: Number 1: -5 plus 7= 2 Number 2: -5 minus 7= -12 Your answer is X=2, -12
x2_12x-3 = 0 Using the formula for solving quadratics: x = 12 plus/minus sqrt (144 - (4 x 1 x -3))/2 x = 12 plus/minus (sqrt 156)/2 x = 12 + (sqrt 156)/2 = 12.25 or x = 12 - (sqrt 156)/2 = -0.25
x squared minus 12 x plus 36 = (x - 6)(x - 6)
133
(x + 12)(x - 3)
(x - 5)(x + 12)
-22 - 12 = -8
X=-3
12 squared plus 18 squared is equal to 468.
(6x - 1)(6x - 1)
It is x^2 -13x +12 = (x-1)(x-12) when factored
Let square = [x] -4+3*(-2)*[-4]+[3x-2x]=-4-6-2+[x]=-12+[x]The answer is negative 12 plus squared x.
a2 + 62 = 122 a2 + 62 - 62 = 122 - 62 a2 = 144 - 36 a2 = 108 taking the square root of each side, we get a equal plus or minus the square root of 108, or plus or minus 6 times the square root of 3.
It is a quadratic equation in X, with two real roots.