Math and Arithmetic
Algebra
Calculus

# What is y x y x y?

y^3

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Y3

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Y3

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Y5

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y×y×y

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Y3

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Rf

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Yxyxy

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3y

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Y3

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Fgg

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## Related Questions

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(x2 - y2)/(x - y) = (x + y)(x - y)/(x - y) = x + y

y = sin(x+y) cos( x + y )[(1 + y')] = y' cos(x + y ) + y'cos(x + y ) = y' y'-y'cos( x+ y) = cos( x + y ) y'[1-cos(x+y)]= cos(x+y) y'= [cos(x+y)]/ [1-cos(x+y)]

1545(x-y)=3(x&sup2;-y&sup2;) (1545&divide;3)(x-y)=(x&sup2;-y&sup2;) 515(x-y)=(x&sup2;-y&sup2;) 515=(x&sup2;-y&sup2;)&divide;(x-y)

Given two numbers, x and y their difference is |x - y|. |x - y| = x - y if X &acirc;&permil;&yen; y and |x - y| = y - x if x &lt; y

There are two simple strategies to compare two numbers, X and Y: you can calculate X - Y. If X - Y &gt; 0 then X &gt; Y, if X - Y = 0 then X = Y and if X - Y &lt;0 then X &lt; Y. Or you can calculate X/Y. Provided both are greater than 0, if X/Y &gt; 0 then X &gt; Y if X/Y = 1 then X = Y if X/Y &lt;1 then X &lt; Y

Your question is like this:X+Y=15, X-Y=5, (X x Y)-X+Y= ?According to my calculations, X=10 and Y=5, therefore (X x Y)-X+Y= 45.

x^(4)*y*x^(5)*yMultiply x^(4) by y to get x^(4)y.(d)/(dx) x^(4)*y*x^(5)*y=x^(4)y*x^(5)*yMultiply x^(4)y by x^(5) to get x^(9)y.(d)/(dx) x^(4)*y*x^(5)*y=x^(9)y*yMultiply x^(9)y by y to get x^(9)y^(2).(d)/(dx) x^(4)*y*x^(5)*y=x^(9)y^(2)To find the derivative of x^(9)y^(2), multiply the base (x) by the exponent (9), then subtract 1 from the exponent.(d)/(dx) x^(4)*y*x^(5)*y=9x^(8)y^(2)The derivative of x^(4)*y*x^(5)*y is 9x^(8)y^(2).9x^(8)y^(2)

1. Calculate X % of Y X per cent of Y = X*Y/100 This implies that X% of Y is the same as Y% of X. 2. X and Y are given. What is X as a percentage of Y? X, as a percentage of Y = 100*X/Y

The commutative property states that X * Y = Y * XThe commutative property states that X * Y = Y * XThe commutative property states that X * Y = Y * XThe commutative property states that X * Y = Y * X

So basically, when you stir a solution, it physically moves all of the chemicals around so the atoms of each are more evenly spread throughout the solution. imagine X represents one reactant, and Y represents the other reactant. Before stirring, they are mixed like this : X X X X X Y X Y X Y X Y Y Y Y Y After Stirring they are like this : X Y X Y X Y X Y X Y X Y X Y X Y X Y so more of the X molecules are next to more of the Y molecules so the reaction happens quicker.

x - y = 5x^2 - y^2 = 5Subtract the first equation from the second equation.x^2 - y^2 - x - (-y) = 5 - 5(x^2 - y^2) - (x - y) = 0(x - y)(x + y) - (x - y) = 0(x - y)(x + y - 1) = 0x - y = 0 or x + y - 1 = 0x = y do not satisfy both equations of the system, so x cannot be equal to y. Thus we need to find the values of x and y for which x + y - 1 = 0 is true.x + y - 1 = 0x = 1 - ySubstitute 1 - y for x to x - y = 5.x - y = 51 - y - y = 5- 2y = 4y = -2Substitute -2 for y to x = 1 - yx = 1 - yx = 1 -(-2)x = 3Thus the solution of the system is (3, -2).

If x and y are additive opposites, then y = -x.If x >= 0 then abs(x) = xalso y andif x also y > 0 so that abs(y) = y.

Commutative x + y = y + x x . y = y . x Associative x+(y+z) = (x+y)+z = x+y+z x.(y.z) = (x.y).z = x.y.z Distributive x.(y+z) = x.y + x.z (w+x)(y+z) = wy + xy + wz + xz x + xy = x x + x'y = x + y where, x &amp; y &amp; z are inputs.

Let x and y be two positive numbers. The cases are: x &gt; y, then x - y &gt; 0 x = y, then x - y = 0 x &lt; y, then x - y &lt; 0

If y is a multiple of x, the LCM of x and y is y.

Let [x percent of y] = (x/100)*y. And [y percent of x] = (y/100)*x.Use the ruSo the first one (x/100)*y = y*(x /100) = y*x/100.The second one: (y/100)*x = x*(y/100) = x * y / 100, which equals y*x/100.So yes they equal the same thing, so they are equal.

(x^2 - y^2) / (x - y) Apply the difference of squares formula: (x + y)(x - y) / (x - y) Assuming x is not equal to y, we can cancel terms leaving x + y When x = y, the denominator becomes 0, and the equation gives no information.

x + y = 9x + y9x + y = x + y8x + y = y8x = 0x = 0

If y is a function of x, that is y=f(x), then the derivative of x-y is 1-y' or 1-dy/dx (where y' or dy/dx is the differential coefficient of y with respect to x).

There are an infinite number of them. Here are a few: x=0, y=-4 x=1, y=-3 x=2, y=-2 x=3, y=-1 x=4, y=0 x=5, y=+1 x=6, y=2 x=7, y=3 x=8, y=4 x=9, y=5 x=9.1, y=5.1 x=9.123, y=5.123 x=9.26704, y=5.26704 x=9.1415926535, y=5.1415926535 . . etc.