Really can't say. You would have to include how many credits the courses are worth. Each grade has specific quality points assigned. In other words an A is worth 12 quality points, a B+ is 10.5, a B is 9, etc. You take the total amount of quality points and divide that number by the total credits taken. So, the number of credits are needed to determine the GPA. Some courses are three credits, others are four, while still others can be one or two credits.
It depend on the number of credits each subject is and the exact valve (%). But it could be around 75%.
Your cumulative GPA is 2.7.
It equals to a low B 4 = A 3 = B 2 = C 1 = D 0 = F
Your GPA would be 1.00 A's get 4 points and F's get zero so your total is 4 / 4 classes = 1.0
Lots. A = 4; B = 3; C = 2; D = 1; F =0. So if one had an A, a C, and a B, their GPA would be 3.0 (B)
It equals to a low B 4 = A 3 = B 2 = C 1 = D 0 = F
On a GPA scale where A = 4 B = 3 C = 2 and D = 1 then the GPA is (4 + 4 + 4 + 1 + 2 + 2 + 2) divided by 7 = 2.71
On a scale for GPA where A =4,B=3,C=2, and D=1 then GPA = (4 x2) + (3 x 3) + (2x2) all divided by 7 to get average GPA = 3.0
If an A = 4 you have (3 + 2 + 2 +1)/4 = 8/4 = 2.0 GPA
First the 'values' of the GPA system:A = 4 pointsB = 3 pointsC = 2 pointsD = 1 pointF = 0 pointsSo, add the sum of the points and divide by the total number of entries. So In this particular question: 3 x 2 = 6 (for the 3 C's) + 4 + 3 + 1 + 0.So ... 6+4+3+1+0 = 14. Now divide that by the total entries (7) and you get 2, or a C grade average.
Given the function f(x) = 2x + 3 and a = -1, we can find f(a) as follows: f(a) = 2(-1) + 3 f(a) = -2 + 3 f(a) = 1 So, f(a) = 1. To graph f(x) and 1/f(x), we can plot several points and connect them to visualize the functions. Here are some points for f(x): For f(x): When x = -2, f(x) = 2(-2) + 3 = -1 When x = -1, f(x) = 2(-1) + 3 = 1 When x = 0, f(x) = 2(0) + 3 = 3 When x = 1, f(x) = 2(1) + 3 = 5 When x = 2, f(x) = 2(2) + 3 = 7 Now, to find 1/f(x), we take the reciprocal of each f(x) value: For 1/f(x): When x = -2, 1/f(x) = 1/(-1) = -1 When x = -1, 1/f(x) = 1/1 = 1 When x = 0, 1/f(x) = 1/3 ≈ 0.333 When x = 1, 1/f(x) = 1/5 ≈ 0.2 When x = 2, 1/f(x) = 1/7 ≈ 0.143 Now, we can plot these points and connect them to obtain the graphs of f(x) and 1/f(x).
3/6 + 1/f = 1/2 + 1/f = (f+2)/2f
F-