0 °C is equal to 32 °F or 273.15 Kelvin.(it would also be equal to 491.67 Rankine)
-273 °C is - 459.5 °F *Absolute zero (0 K) is -273.15 °C or -459.67 °F
−273.15 °C i was taught zero k was -273.16 deg c
F to C: Deduct 32, then multiply by 5, then divide by 9 C to F: Multiply by 9, then divide by 5, then add 32 C = K - 273.15 K = C + 273.15 F to K: Change to Celsius, add 273.15
zero K or -273.15 C
Absolute zero = 0 K = -273.15°C
0 K is equal to -459.67 °F The theoretical temperature "absolute zero" is 0 K, -273.15 °C, or -459.67 °F. 0°K = -459.67°F = -273.15 °C
C to F: F = 1.8*C + 32C to K: K = C - 273.15 F to C: C = 5/9*(F- 32) F to K: K = 5/9*(F- 32) - 273.15 K to C: C = K + 273.15 K to F: K = 1.8*(K - 273.15) + 32
0 °C is equal to 32 °F or 273.15 Kelvin.(it would also be equal to 491.67 Rankine)
Why don't you tell us? I bet you know... -_-
It is k*f/k where k is any non-zero number.
Absolute Zero = 0 K = −273.15°C = −459.67°F
f f f f f f u u u u c c c c k k k k
Absolute zero is 0 K, -273.15 C and -459.67 F
Absolute zero; about -460 F, -273 C, or 0 K
57 K = -357.07 °FThe zero point for Kelvin is absolute zero or -273.15 °C / -459.67 °F and57 K = - 216.15 °C which converts to -357.07 °F by the formulaFahrenheit temperature = (9/5 x Celsius temperature)+ 32
-273 °C is - 459.5 °F *Absolute zero (0 K) is -273.15 °C or -459.67 °F