-273.15 c
-459.67 f
0 °C is equal to 32 °F or 273.15 Kelvin.(it would also be equal to 491.67 Rankine)
-273 °C is - 459.5 °F *Absolute zero (0 K) is -273.15 °C or -459.67 °F
F to C: Deduct 32, then multiply by 5, then divide by 9 C to F: Multiply by 9, then divide by 5, then add 32 C = K - 273.15 K = C + 273.15 F to K: Change to Celsius, add 273.15
Platinum (Pt) Melting points: 2041.4 K, 1768.3 °C, 3214.9 °F Boiling points: 4098 K, 3825 °C, 6917 °F
approximately -9 C 0 C = 32 F half of 32 F is 16 F The formula for calculating Celsius from Fahrenheit is C = 5/9(Fahrenheit - 32) so C = 5/9 (16-32) = 5/9 X -16 = -8.889 C
Absolute zero = 0 K = -273.15°C
0 K is equal to -459.67 °F The theoretical temperature "absolute zero" is 0 K, -273.15 °C, or -459.67 °F. 0°K = -459.67°F = -273.15 °C
100 K is the lowest, as it is in Kelvin scale which has the lowest absolute zero point. 100 C is equivalent to 373 K and 100 F is equivalent to 310 K, so 100 K is the lowest of the three temperatures.
Why don't you tell us? I bet you know... -_-
It is k*f/k where k is any non-zero number.
C to F: F = 1.8*C + 32C to K: K = C - 273.15 F to C: C = 5/9*(F- 32) F to K: K = 5/9*(F- 32) - 273.15 K to C: C = K + 273.15 K to F: K = 1.8*(K - 273.15) + 32
Absolute Zero = 0 K = −273.15°C = −459.67°F
Absolute zero is 0 K, -273.15 C and -459.67 F
57 K = -357.07 °FThe zero point for Kelvin is absolute zero or -273.15 °C / -459.67 °F and57 K = - 216.15 °C which converts to -357.07 °F by the formulaFahrenheit temperature = (9/5 x Celsius temperature)+ 32
absolute zero, 0 °K, -273.15 °C, or −459.67 °F
0 °C is equal to 32 °F or 273.15 Kelvin.(it would also be equal to 491.67 Rankine)
Since absolute zero is -273.15 °C and 0 °K, 278 K approximately the same as 5 °C. On the Fahrenheit scale, it would be equal to 41 °F.