The way to solve these problems is to determine which reactant will produce the fewest moles of product. In order to do this, we first need to convert the mass of each reactant into moles of reactant using the molecular mass of silver, Ag (107.9 g/mol), and molecular sulfur, S8 (256.5) g/mol:
2.0 g Ag * 1mol/107.9 g/mol = 0.0185 mol Ag
2.0 g S8 * 1mol/256.5 g/mol = 0.00779 mol S8
Now using the balanced chemical equation (our recipe) from above:
16 Ag + S8 -->8 Ag2S
We can see:
16 moles of Ag turns into 8 moles of Ag2S
1 mole of S8 turns into 8 moles of Ag2S
What we need to do know, is use these two statements above to see how many moles of product each reactant turns into:
0.0185 mol Ag * 8 mol Ag2S/16 mol Ag = 0.00925 mol Ag2S
0.00779 mol S8 * 8mol Ag2S/1 mol S8 = 0.0623 mol Ag2S
Since 0.0185 mole of Ag produce less Ag2S (the product), silver (Ag) is the limiting reactant. Now you could convert this to grams of product by multiplying the lesser amount produced, 0.00925 moles of Ag2S, by the molecular mass of Ag2S.
To determine the mass of reactant left unreacted, we need to convert moles of the limiting reactant into moles of the other reactant to find out how much of the other reactant is lost--Then subtract from the original amount and convert to grams with the molecular mass.
0.0185 mol Ag * 1 mol S8/16 mol Ag = 0.00116 mol S8
Originally we had 0.00779 mol of S8, from above, so:
0.00779 mol S8 - 0.00116 mol S8 = 0.00663 mol S8
Now convert to grams left:
0.00663 mol S8 * 256.5 g/mol = 1.70 g S8 left unreacted!
20g I think
To calculate the mass of an atom, 1amu = 1.66*10^-24 and sodium has a mass of 22.99amu. Therefore, 425 sodium atom would be 425*(22.99*(1.66*10^-24))=1.6219445~-20. With the sig fig, the final answer is: 1.62*10^-20g
0.401
3.5g NaCl , 1.5g KCl , 2.5g NaHCO3 , 20g glucose. Add these components to 1 liter of water.
there is 20g of sugar in sunny delight(12 tbs of sugar)
20g
what is the density of an 0bject that has a mass of 20g and a volume pf 10mL?
Density = mass/volume = 20g/8cm3 = 2.5 grams per cm3
Density is mass per unit volume. If 10 cm3 weighs 20g, the density is 2 g/cc.
Mass solution=100g Mass solution=20g Mass Mass % = (mass Of solute/mass Of solution ) x 100. =(20/100)x100 =1/5 x 100. =100/5 =20%
The formula of mercury (II) oxide is HgO, showing that one oxygen atom is present for each mercury atom. The gram atomic mass of mercury is 200.59 and that of oxygen is 15.9994. Therefore, the mass of oxygen produced will be: 18.6(15.9994/200.59) = 1.48g of oxygen, to the justified number of significant digits. The sum of 1.48g and 18.6g is 20.08, which rounded to two significant digits is 20g, indicating that the decomposition was complete.
20g is the mass and the volume is 10cm^3 its like asking how do i spell pigeon
Approximately 20g, but this fluctuates with temperature
Density = (mass) / (volume) = 20/80 = 0.25 g/cc
The mass of lithium oxide (Li2O) is 8,o9 g.
Denisty = Mass/Volume = 20/4 = 5 g/cm3
If 20g of mercury oxide were heated, the combined mass of oxygen and mercury would be 20 grams.