initial volume = V1
final volume = V2
initial pressure = P1
final pressure = P2 = (1/2)P1
P1V1 = P2V2
P1V1 = (1/2)P1V2
P1 cancels;
V1 = (1/2)V2
V2 = 2V2.
20psi
If the volume of a container of air is reduced by one half the partial pressure of the oxygen with in the container will be doubled. If the volume of a container of gas is reduced, the pressure inside the container will increase.
"For a fixed mass of ideal gas at fixed temperature, the product of pressure and volume is a constant." This means that if you have a container with an ideal gas in it, and the container is closed so that no gas can escape or get int (i.e. the mass of the gas contained is constant), when you raise the volume of the container by some ratio, the pressure will be reduced by the same ratio. So if you triple the volume, the pressure will be reduced to a third of its original value. And if you quadruple the pressure, the volume will go down by a factor of 4.
This problem can be solved with the ideal gas law. The original pressure and volume of the container are proportional the final pressure and volume of the container. The original pressure was 1 atmosphere and the original volume was 1 liter. If the final volume is 1.8 liters, then the final pressure is 0.55 atmospheres.
The pressure inside the container will increase. Pressure (P) is force(F) divided by the area(A) it hits on. If you decrease the area, you increase the pressure.
The pressure is reduced to one third of the original pressure. The pressure will stay the same you are only changing the volume
The pressure is reduced to one third of the original pressure. The pressure will stay the same you are only changing the volume
Pressure is due to the bombardment of molecules on the walls of the container. So when the volume is reduced then naturally the surface area will be reduced. Pressure is the force measured per unit area. Hence reducing volume would bring a decrease in its surface area and so the pressure increases. So volume and pressure are getting related.
In a small volume container the pressure is higher.
As the volume is decreased, the same number of molecules of air have a smaller space to move freely in. The number of collisions of molecules of air with the walls of the container per unit time increases. Since pressure is the force exerted over an area, the pressure increases.
it doublesIf the mass of the air remains constant, the PPO2 doubles.
If you increase the volume of the container, and not the gas itself, then the pressure decreases. If you increase the volume of the gas, and not the container, then the pressure increases.