3
Only the number 8 (VIII)
When you spell out the words for numbers 1-10 four of the numbers have three letters. (one two six ten)
11
four, five, nine :)....and zero
This is the answer:OTTFFSSENT are the letters representing the first letter of the numbers 1 through 10.
3. Three, Seven, Eight.
There is none
3 This are Three, Seven, and Eight.
In the word "gallipolis"there are 10 letters (n =10)."l" appears 3 times (n1 =3)."i" appears 2 times (n2 =2).And 5 letters appear once (n3 =1, n4 =1, n5 =1, n6 =1, n7 =1)The number of permutations that can be made with these 10 letters is;P =n!/(n1!n2!n3!n4!n5!n6!n7!) =10!/(3!∙2!∙1!∙1!∙1!∙1!∙1!) =302 400
The number 249 in hexadecimal would be F9. The digits in base 16 correspond to powers of 16 rather than 10. For a two-digit number, the place values are 16 and 1, and the usable values are from 0 to 15, with values 10 through 15 represented by letters A (10) through F (15). F9 = (15x16) + (9x1) = 240 + 9
The smallest number that is divisible by the numbers 1 through 10, except 7 and 8, is 180.
BASKETBALL = 10 letters B=2 A=2 S=1 K=1 E=1 T=1 L=2 Number of permutations = 10! /2!2!2! = 10x9x8x7x6x5x4x3x2 / 2x2x2 =3,628,800 / 8 =453,600