Vi = 6
iii = 3
(vi)iii (vi)iii = 1000*6+3 = 6003
The chord progression for a song that includes the I, VI, III, and V chords is typically written as I - VI - III - V.
The chord progression in the key of IV that includes the chords V, III, and VI is V-III-VI.
I, II, III, IV, V, VI, VII, VIII IX, XI, II, III, IV, V, VI, VII, VIII IX, XI, II, III, IV, V, VI, VII, VIII IX, XI, II, III, IV, V, VI, VII, VIII IX, XI, II, III, IV, V, VI, VII, VIII IX, XI, II, III, IV, V, VI, VII, VIII IX, X
III-XXVIIII-VI or III-IXXX-VI. Note that 29 in Roman numerals is not XXIX.
(VI)III
The chord progressions for the key of A major that include the i, iii, and vi chords are Am - C - F.
first 50 numbers of pi in roman numerals III. I IV I V II VI V III V VIII IX VIII IX III II III III VIII IV VI II VI IV III III VIII III II VII IX V NULLA II VIII VIII IV I IX VII I IX III IX IX III VII V I NULLA
no
The answer is 174.DXXII/III = (C + LX + VI + II/III) + (III + I/III) + (III + I/III) + II/III = CLXXIVDXXII/III == D/III + X/III + X/III + II/III == (CxV)/III + (III + I/III) + (III + I/III) + II/III == Cx(V/III) + VII + I/III == Cx(I + II/III) + VII + I/III == C + (CxII)/III + VII + I/III == C + ((XxX)xII)/III + VII + I/III == C + Xx(XxII)/III + VII + I/III == C + Xx(VI + II/III) + VII + I/III == C + LX + (XxII)/III + VII + I/III == C + LX + VI + II/III + VII + I/III == CLXXIV
Rhodium (VI) Chloride
9 - 3 = 66 = vi