Any number of the form 58*k where k is an integer.
Itself and any of its multiples
Multiples of 58.
The lists of numbers divisible by and not divisible by 600 are both infinite.
All even numbers are divisible by 2.
Odd numbers
51234 is divisible by itself and any of its multiples
Every number is divisible by any non-zero number. Any element of the set of numbers of the form 4518*k where k is an integer is evenly divisible.
177 is divisible by all of its factors, which are 1, 3, 59, and 177.
yes the answer is 59. because numbers that end in five and zero are divisible by 5.
The sum of three consecutive odd numbers must be divisible by 3. As 59 is not wholly divisible by 3 the question is invalid. PROOF : Let the numbers be n - 2, n and n + 2. Then the sum is 3n which is divisible by 3. If the question refers to three consecutive numbers then a similar proof shows that the sum of these three numbers is also divisible by 3. Again, the question would be invalid.
2065 is obviously divisible by 5, so start there 2065 / 5 = 413 413 / 7 = 59 59 is prime. Factorization is [5 7 59] factors are [1 5 7 35 59 413 2065]
Yes, it is divisible by "1" and by "59" making it a prime number.
No. 708 is divisible by these numbers: 1, 2, 3, 4, 6, 12, 59, 118, 177, 236, 354, 708.
118 is divisible by these numbers: 1 2 59 and 118.
U={whole number greater than 10 but smaller than 30 } X={numbers divisible by 3 } Y Odd numbers
All numbers are divisible by 1.
All even numbers can be eliminated immediately because they are all divisible by 2. All numbers that end in 5 can be eliminated because they are divisible by 5. All numbers whose digits when added together are divisible by 3 can be eliminated because the number is divisible by 3. 53, 59, 61 67, 71 are the prime numbers.
You can elimate the even numbers 72 and 42 right away because the only even prime number is 2. Using the divisibility rules, you can eliminate 87; 8 + 7 = 15, which is divisible by 3, which means 87 is divisible by 3. 59 is the prime number.
59 and 89 are prime numbers because they have exactly two factors, 1 and the number itself. Another test is that they are not evenly divisible by 2, 3, 5, or 7, which are the only prime numbers smaller than their square roots.