1, 2, 4, 8, 16, 32 (1 x 32, 2 x 16, 4 x 8)
1, 2, 4, 8, 16, 32 (1 x 32, 2 x 16, 4 x 8)
There are no real numbers possible for this combination. Since the quadratic eqn x^2+8x+32=0 have only complex value as their roots. The roots are (-4-4i) and (-4+4i)
Five twos.
32, 64, 96, 128, 160, 192, 224, 256, 288, 320 . . .
False.
16 doesn't have a GCF. You need at least two numbers to find one of those. If you're asking what three numbers equal 16, there are an infinite number of possibilities. If you're asking what three numbers have a GCF of 16, 16, 32 and 48 is one answer.
-30
137
1 & 512, 2 & 256, 4 & 128, 8 & 64, 16 & 32
-28
16 and 2
34
962
There are infinitely many pairs. Suppose x is any non-zero number. Let y = 32/x. Then x*y = x*(32/x) = 32 Then there are infinitely many sets of 3 numbers, of 4 numbers, etc.
4 x 8 = 32
no 3 numbers add to equal 10 and multiply to equal 40.
The two numbers you can multiply together to equal 782 are 23 by 34.
The two numbers you multiply together to equal 391 are 17 by 23.